POJ1753【简单DFS算法】--翻棋盘（一步看不懂！！）

                                                                                                         Flip Game

Time Limit: 1000MS		Memory Limit: 65536K
Total Submissions: 35877		Accepted: 15658

Description

Flip game is played on a rectangular 4x4 field with two-sided pieces placed on each of its 16 squares. One side of each piece is white and the other one is black and each piece is lying either it's black or white side up. Each round you flip 3 to 5 pieces, thus changing the color of their upper side from black to white and vice versa. The pieces to be flipped are chosen every round according to the following rules: 

1. Choose any one of the 16 pieces. 
2. Flip the chosen piece and also all adjacent pieces to the left, to the right, to the top, and to the bottom of the chosen piece (if there are any).

Consider the following position as an example: 
bwbw  wwww  bbwb  bwwb  Here "b" denotes pieces lying their black side up and "w" denotes pieces lying their white side up. If we choose to flip the 1st piece from the 3rd row (this choice is shown at the picture), then the field will become: 
bwbw  bwww  wwwb  wwwb  The goal of the game is to flip either all pieces white side up or all pieces black side up. You are to write a program that will search for the minimum number of rounds needed to achieve this goal. 

Input

The input consists of 4 lines with 4 characters "w" or "b" each that denote game field position.

Output

Write to the output file a single integer number - the minimum number of rounds needed to achieve the goal of the game from the given position. If the goal is initially achieved, then write 0. If it's impossible to achieve the goal, then write the word "Impossible" (without quotes).

Sample Input

bwwb
bbwb
bwwb
bwww

Sample Output

4

Source

Northeastern Europe 2000

 

题意：每次翻一个棋子的上下左右和它自己，直到全为一种颜色

 

#include <stdio.h>

const int inf=9999999;
char s[10];
int map[10][10],i,j;
int ans=9999999;

int panduan()
{
    int x=map[0][0];
    for (i=0; i<4; i++)
    {
        for (j=0; j<4; j++)
        {
            if (map[i][j]!=x)
                return 0;
        }
    }
    return 1;
}

void fan (int x,int y)
{
    map[x][y]=!map[x][y];
    if (x - 1 >= 0)
        map[x-1][y]=!map[x-1][y];
    if (x + 1 < 4)
        map[x+1][y]=!map[x+1][y];
    if (y - 1 >= 0)
        map[x][y-1]=!map[x][y-1];
    if (y + 1 < 4)
        map[x][y+1]=!map[x][y+1];
}

int dfs (int x,int y,int t)
{
    int nx,ny;
    if ( panduan()==1)
    {
        if (ans > t)
            ans = t ;
        return 0;
    }
    if (x >= 4 || y >= 4)
        return 0;

    nx = (x + 1)%4;
    ny = y + ( x + 1 ) / 4;

    dfs (nx,ny,t);//两次dfs不知道啥意思。。。
    fan (x,y);

    dfs (nx,ny,t+1);
    fan (x,y);

    return 0;
}
int main ()
{
    for (i=0; i<4; i++)
    {
        scanf ("%s",s);
        for (j=0; j<4; j++)
        {
            if (s[j]=='b')
                map[i][j]=0;
            else
                map[i][j]=1;
        }
    }
    dfs (0,0,0);

    if (ans == inf )
        printf ("Impossible
");
    else printf ("%d
",ans);
    return 0;
}