zoukankan      html  css  js  c++  java
  • 1036 Boys vs Girls (25 分)

    1036 Boys vs Girls (25 分)

    This time you are asked to tell the difference between the lowest grade of all the male students and the highest grade of all the female students.

    Input Specification:

    Each input file contains one test case. Each case contains a positive integer N, followed by N lines of student information. Each line contains a student's name, gender, ID and grade, separated by a space, where name and ID are strings of no more than 10 characters with no space, gender is either F (female) or M (male), and grade is an integer between 0 and 100. It is guaranteed that all the grades are distinct.

    Output Specification:

    For each test case, output in 3 lines. The first line gives the name and ID of the female student with the highest grade, and the second line gives that of the male student with the lowest grade. The third line gives the difference gradeF​​gradeM​​. If one such kind of student is missing, output Absent in the corresponding line, and output NA in the third line instead.

    Sample Input 1:

    3
    Joe M Math990112 89
    Mike M CS991301 100
    Mary F EE990830 95
    

    Sample Output 1:

    Mary EE990830
    Joe Math990112
    6
    

    Sample Input 2:

    1
    Jean M AA980920 60
    

    Sample Output 2:

    Absent
    Jean AA980920
    NA
    #include<iostream>
    #include<vector>
    #include<algorithm>
    #include<queue>
    #include<string>
    #include<map>
    #include<set>
    #include<stack>
    #include<string.h>
    #include<cstdio>
    #include<cmath>
    using namespace std;
    struct Student
    {
        string name;
        string id;
        int grade;
    };
    bool cmp(Student&A,Student&B)
    {
        return A.grade<B.grade;
    }
    
    
    
    int main()
    {
        int n;
        cin>>n;
        vector<Student> males,females;
        Student temp;
        char sex;
        for(int i=0;i<n;i++)
        {
            cin>>temp.name>>sex>>temp.id>>temp.grade;
            if(sex=='M')
                males.push_back(temp);
            else
                females.push_back(temp);
        }
        sort(males.begin(),males.end(),cmp);
        sort(females.begin(),females.end(),cmp);
        bool flag=false;
        if(females.size()==0)
        {
            cout<<"Absent"<<endl;
            flag=true;
        }
        else
            cout<<females[females.size()-1].name<<" "<<females[females.size()-1].id<<endl;
        if(males.size()==0)
        {
            cout<<"Absent"<<endl;
            flag=true;
        }
        else
            cout<<males[0].name<<" "<<males[0].id<<endl;
        if(flag)
            cout<<"NA"<<endl;
        else
            cout<<females[females.size()-1].grade-males[0].grade<<endl;
        return 0;
    }

      
  • 相关阅读:
    尤埃开放服务平台(OSGi.NET)带给您的价值
    用C#实现的条形码和二维码编码解码器
    php基本语法
    大型网站核心技术
    大型公司里开发和部署前端代码——引自前百度前端工程师
    Python基础 函数
    Python 循环
    Binary Agents
    Steamroller
    Drop it
  • 原文地址:https://www.cnblogs.com/zhanghaijie/p/10324667.html
Copyright © 2011-2022 走看看