zoukankan      html  css  js  c++  java
  • 1089 Insert or Merge (25 分)

    1089 Insert or Merge (25 分)

    According to Wikipedia:

    Insertion sort iterates, consuming one input element each repetition, and growing a sorted output list. Each iteration, insertion sort removes one element from the input data, finds the location it belongs within the sorted list, and inserts it there. It repeats until no input elements remain.

    Merge sort works as follows: Divide the unsorted list into N sublists, each containing 1 element (a list of 1 element is considered sorted). Then repeatedly merge two adjacent sublists to produce new sorted sublists until there is only 1 sublist remaining.

    Now given the initial sequence of integers, together with a sequence which is a result of several iterations of some sorting method, can you tell which sorting method we are using?

    Input Specification:

    Each input file contains one test case. For each case, the first line gives a positive integer N (100). Then in the next line, N integers are given as the initial sequence. The last line contains the partially sorted sequence of the N numbers. It is assumed that the target sequence is always ascending. All the numbers in a line are separated by a space.

    Output Specification:

    For each test case, print in the first line either "Insertion Sort" or "Merge Sort" to indicate the method used to obtain the partial result. Then run this method for one more iteration and output in the second line the resuling sequence. It is guaranteed that the answer is unique for each test case. All the numbers in a line must be separated by a space, and there must be no extra space at the end of the line.

    Sample Input 1:

    10
    3 1 2 8 7 5 9 4 6 0
    1 2 3 7 8 5 9 4 6 0
    

    Sample Output 1:

    Insertion Sort
    1 2 3 5 7 8 9 4 6 0
    

    Sample Input 2:

    10
    3 1 2 8 7 5 9 4 0 6
    1 3 2 8 5 7 4 9 0 6
    

    Sample Output 2:

    Merge Sort
    1 2 3 8 4 5 7 9 0 6
    思路:
      1、使用sort函数,减少错误
      2、模拟归并排序,主要是为了找出步长。
    #include<iostream>
    #include<string>
    #include<vector>
    #include<string>
    #include<cstdio>
    #include<cmath>
    #include<string.h>
    #include<algorithm>
    using namespace std;
    int main()
    {
        int n;
        scanf("%d",&n);
        int a[n+1];
        for(int i=1; i<n+1; i++)
            scanf("%d",&a[i]);
        int b[n+1];
        for(int i=1; i<n+1; i++)
            scanf("%d",&b[i]);
        int p=1;
        while(p<n&&b[p]<=b[p+1])
            p++;
        // printf("%d
    ",p);
        int temp=p;
        int index=p+1;
        while(index<n+1&&a[index]==b[index])
            index++;
        if(index==n+1)
        {
            sort(b+1,b+p+2);
            printf("Insertion Sort
    ");
            printf("%d",b[1]);
            for(int i=2; i<n+1; i++)
                printf(" %d",b[i]);
        }
        else
        {
            int k=2*p;
            printf("Merge Sort
    ");
            bool flag=false;
            for(int step=2;step/2<=n;step*=2)
            {
                if(step!=2)
                {
                    for(int i=1;i<n+1;i++)
                    {
                        if(a[i]!=b[i])
                            break;
                        if(i==n)
                            flag=true;
                    }
                }
                for(int i=1;i<n+1;i+=step)
                {
                    sort(a+i,a+min(i+step,n+1));
                }
                if(flag)
                    break;
            }
    
    
            printf("%d",a[1]);
            for(int i=2; i<n+1; i++)
                printf(" %d",a[i]);
    
        }
        return 0;
    }

      
  • 相关阅读:
    [置顶] Extjs4 异步刷新书的情况下 保持树的展开状态
    控制系统中常用的名词术语
    开环控制系统与闭环控制系统
    反馈控制
    Tensorflow把label转化成one_hot格式
    Tensorflow——tf.nn.max_pool池化操作
    Tensorflow——tf.nn.conv2d卷积操作
    Tensoflow简单神经网络实现非线性拟合
    Tensorflow 中的 placeholder
    Tensorflow 中的constant、Session、placeholde和 Variable简介
  • 原文地址:https://www.cnblogs.com/zhanghaijie/p/10374580.html
Copyright © 2011-2022 走看看