nyoj 5 Binary String Matching

Binary String Matching

时间限制：3000 ms  |  内存限制：65535 KB

难度：3

描述

Given two strings A and B, whose alphabet consist only ‘0’ and ‘1’. Your task is only to tell how many times does A appear as a substring of B? For example, the text string B is ‘1001110110’ while the pattern string A is ‘11’, you should output 3, because the pattern A appeared at the posit

输入

The first line consist only one integer N, indicates N cases follows. In each case, there are two lines, the first line gives the string A, length (A) <= 10, and the second line gives the string B, length (B) <= 1000. And it is guaranteed that B is always longer than A.

输出

For each case, output a single line consist a single integer, tells how many times do B appears as a substring of A.

样例输入

3

11

1001110110

101

110010010010001

1010

110100010101011

样例输出

3

0

3 

#include<stdio.h>
#include<string.h>
int main()
{
    int N;
    scanf("%d",&N);
    while(N--)
    {
        int i,j,count=0;
       char a[10],b[1000];
        scanf("%s",&a);
       scanf("%s",&b);
            for(j=0;j<strlen(b);j++)
            {
                for(i=0;i<strlen(a);i++)
                if(b[j+i]!=a[i]){i++;break;}
                if(b[j+i-1]==a[i-1])
					count++;
            }

        printf("%d
",count);
    }
    return 0;
}