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  • POJ 2121

    Inglish-Number Translator
    Time Limit: 1000MS   Memory Limit: 65536K
    Total Submissions: 5162   Accepted: 2027

    Description

    In this problem, you will be given one or more integers in English. Your task is to translate these numbers into their integer representation. The numbers can range from negative 999,999,999 to positive 999,999,999. The following is an exhaustive list of English words that your program must account for:
    negative, zero, one, two, three, four, five, six, seven, eight, nine, ten, eleven, twelve, thirteen, fourteen, fifteen, sixteen, seventeen, eighteen, nineteen, twenty, thirty, forty, fifty, sixty, seventy, eighty, ninety, hundred, thousand, million

    Input

    The input consists of several instances. Notes on input:
    1. Negative numbers will be preceded by the word negative.
    2. The word "hundred" is not used when "thousand" could be. For example, 1500 is written "one thousand five hundred", not "fifteen hundred".

    The input is terminated by an empty line.

    Output

    The answers are expected to be on separate lines with a newline after each.

    Sample Input

    six
    negative seven hundred twenty nine
    one million one hundred one
    eight hundred fourteen thousand twenty two
    
    

    Sample Output

    6
    -729
    1000101
    814022
     
    
    C++string类写
    
    #include <iostream>
    #include <string>
    #include <cstdio>
    
    using namespace std;
    
    
    
    string a[100]={"negative","zero","one","two","three","four","five","six","seven","eight","nine","ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen"
    ,"eighteen","nineteen","twenty","thirty","forty","fifty","sixty","seventy","eighty","ninety","hundred","thousand","million"};
    
    int main(){
    string s;
    int ans=0,sum=0;
    while(cin>>s){
        if(s==a[0])
            cout<<"-";
        else if(s==a[1])
            sum+=0;
        else if(s==a[2])
            sum+=1;
         else if(s==a[3])
            sum+=2;
            else if(s==a[4])
            sum+=3;
            else if(s==a[5])
            sum+=4;
            else if(s==a[6])
            sum+=5;
            else if(s==a[7])
            sum+=6;
            else if(s==a[8])
            sum+=7;
            else if(s==a[9])
            sum+=8;
            else if(s==a[10])
            sum+=9;
            else if(s==a[11])
            sum+=10;
            else if(s==a[12])
            sum+=11;
            else if(s==a[13])
            sum+=12;
            else if(s==a[14])
            sum+=13;
            else if(s==a[15])
            sum+=14;
            else if(s==a[16])
            sum+=15;
            else if(s==a[17])
            sum+=16;
            else if(s==a[18])
            sum+=17;
            else if(s==a[19])
            sum+=18;
            else if(s==a[20])
            sum+=19;
            else if(s==a[21])
            sum+=20;
            else if(s==a[22])
            sum+=30;
            else if(s==a[23])
            sum+=40;
            else if(s==a[24])
            sum+=50;
            else if(s==a[25])
            sum+=60;
            else if(s==a[26])
            sum+=70;
            else if(s==a[27])
            sum+=80;
            else if(s==a[28])
            sum+=90;
    
        else if(s==a[29])
            sum*=100;
        else if(s==a[30])
        {
            ans+=sum*1000;
            sum=0;
        }
        else if(s==a[31])
        {
            ans+=sum*1000000;
            sum=0;
        }
        char ch = getchar();
        if(ch=='
    '){
            cout<<sum+ans<<endl;
            sum=0;
            ans=0;
        }
    }
    return 0;
    }
    
    C的strcmp写
    
    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #define maxn 100
    char s[maxn];
    int sum=0,ans=0;
    int main()
    {
     while(scanf("%s",s)!=EOF)
     {
      if(!strcmp(s,"negative"))printf("-");
      else if(!strcmp(s,"zero"))sum+=0;
      else if(!strcmp(s,"one"))sum+=1;
      else if(!strcmp(s,"two"))sum+=2;
      else if(!strcmp(s,"three"))sum+=3;
      else if(!strcmp(s,"four"))sum+=4;
      else if(!strcmp(s,"five"))sum+=5;
      else if(!strcmp(s,"six"))sum+=6;
      else if(!strcmp(s,"seven"))sum+=7;
      else if(!strcmp(s,"eight"))sum+=8;
      else if(!strcmp(s,"nine"))sum+=9;
      else if(!strcmp(s,"ten"))sum+=10;
      else if(!strcmp(s,"eleven"))sum+=11;
      else if(!strcmp(s,"twelve"))sum+=12;
      else if(!strcmp(s,"thirteen"))sum+=13;
      else if(!strcmp(s,"fourteen"))sum+=14;
      else if(!strcmp(s,"fifteen"))sum+=15;
      else if(!strcmp(s,"sixteen"))sum+=16;
      else if(!strcmp(s,"seventeen"))sum+=17;
      else if(!strcmp(s,"eighteen"))sum+=18;
      else if(!strcmp(s,"nineteen"))sum+=19;
      else if(!strcmp(s,"twenty"))sum+=20;
      else if(!strcmp(s,"thirty"))sum+=30;
      else if(!strcmp(s,"forty"))sum+=40;
      else if(!strcmp(s,"fifty"))sum+=50;
      else if(!strcmp(s,"sixty"))sum+=60;
      else if(!strcmp(s,"seventy"))sum+=70;
      else if(!strcmp(s,"eighty"))sum+=80;
      else if(!strcmp(s,"ninety"))sum+=90;
      else if(!strcmp(s,"hundred"))
      {
        sum*=100;
      }
      else if(!strcmp(s,"thousand"))
      {
       ans+=sum*1000;<pre><span style="color:#008000;">//</span><span style="color:#008000;">当为1000之后,原数应加上num*1000,而非直接乘,1000000也是一样</span>
    
    sum=0; } else if(!strcmp(s,"million")) { ans+=sum*1000000; sum=0; }
    
    //当系统读到回车时,输出 
    
     char ch=getchar(); 
    if(ch=='
    ') 
    {
     printf("%d
    ",ans+sum);
     sum=0; ans=0;
     } 
    }
     return 0;
    }


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  • 原文地址:https://www.cnblogs.com/zhangmingzhao/p/7256435.html
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