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  • 【java开发系列】—— 集合使用方法

    一、首先看一下集合的框架图:

    由于collection也继承了Iterator和comparable接口,因此我们可以使用Iterator来遍历元素,也可以通过自定义compareTo函数来重新编写自己的排序。

    二、代码

    1、List

    package testCollection;
    
    import java.util.ArrayList;
    import java.util.Iterator;
    import java.util.List;
    
    public class testList {
        public static void main(String[] args){
            List list = new ArrayList();
            list.add("test1");
            list.add("test2");
            list.add("test3");
            
            System.out.println("out by for!");
            for(Object o : list){
                System.out.println(o);
            }
            
            System.out.println("out by iterator!");
            Iterator iterator = list.iterator();
            while(iterator.hasNext()){
                String element = (String)iterator.next();
                System.out.println(element);
            }
        }
    }

    运行结果

    out by for!
    test1
    test2
    test3
    out by iterator!
    test1
    test2
    test3

    2、Set,如果遇到重复的元素,不会添加

    package testCollection;
    
    import java.util.HashSet;
    import java.util.Set;
    
    public class testSet {
        public static void main(String[] args){
            Set set = new HashSet();//使用set一般都是用hashset,这个会快一些
            set.add("test1");
            set.add("test2");
            if(set.add("test2")){
                System.out.println("add successful");
            }else{
                System.out.println("add failed");
            }
        }
    }

    运行结果

    add failed

    3、Map

    package testCollection;
    
    import java.util.HashMap;
    import java.util.Map;
    import java.util.Set;
    
    public class testMap {
        public static void main(String[] args){
            Map map = new HashMap();
            
            map.put(1, "test1");
            map.put(2, "test2");
            
            System.out.println("size "+map.size());
            System.out.println(map.get(1));
            
            Set keys = map.keySet();
            for(Object key : keys){
                System.out.println(key);
            }
            
            map.remove(2);
            System.out.println("size "+map.size());
        }
    }

    运行结果

    size 2
    test1
    1
    2
    size 1

    4、自定义排序函数
    person类,继承Comparable接口,重载compareTo函数

    package testCollection;
    
    public class Person implements Comparable{
        private String name;
        private int age;
        public String getName() {
            return name;
        }
        public void setName(String name) {
            this.name = name;
        }
        public int getAge() {
            return age;
        }
        public void setAge(int age) {
            this.age = age;
        }
        public Person(String name,int age){
            this.name = name;
            this.age = age;
        }
        @Override
        public int compareTo(Object person) throws ClassCastException {
            if(!(person instanceof Person)){
                throw new ClassCastException("A Person perspected!");
            }
            int age = ((Person)person).getAge();
            return this.age-age;
        }
    }

    测试类

    package testCollection;
    
    import java.util.Arrays;
    
    public class testComparable {
        public static void main(String[] args){
            Person[] persons = new Person[4];
            persons[0] = new Person("test1",18);
            persons[1] = new Person("test2",20);
            persons[2] = new Person("test3",15);
            persons[3] = new Person("test4",19);
            
            System.out.println("before sorting!");
            
            for(Person p : persons){
                System.out.println("name: "+p.getName()+" age: "+p.getAge());
            }
            
            System.out.println("after sorting!");
            Arrays.sort(persons);
            for(Person p : persons){
                System.out.println("name: "+p.getName()+" age: "+p.getAge());
            }
        }
    }

    运行结果:

    before sorting!
    name: test1 age: 18
    name: test2 age: 20
    name: test3 age: 15
    name: test4 age: 19
    after sorting!
    name: test3 age: 15
    name: test1 age: 18
    name: test4 age: 19
    name: test2 age: 20
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  • 原文地址:https://www.cnblogs.com/zhangxiangguo/p/5401259.html
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