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  • LinkedList add get 源码解析

    public class LinkedList<E>
    extends AbstractSequentialList<E>
    implements List<E>, Deque<E>, Cloneable, java.io.Serializable

    其中Deque为双端队列

    add(E e)方法如下,就是在链表的最后一项,在其next项附上要添加的数据

        /**
         * Appends the specified element to the end of this list.
         *
         * <p>This method is equivalent to {@link #addLast}.
         *
         * @param e element to be appended to this list
         * @return {@code true} (as specified by {@link Collection#add})
         */
        public boolean add(E e) {
            linkLast(e);
            return true;
        }
    
        /**
         * Links e as last element.
         */
        void linkLast(E e) {
            final Node<E> l = last;
            final Node<E> newNode = new Node<>(l, e, null);
            last = newNode;
            if (l == null)
                //如果last节点为空,说明链表是空的,那么新增的数据既是first又是last
                first = newNode;
            else
                //如果last不为空,把新增的元素链接到原来的last的next
                l.next = newNode;
            size++;
            modCount++;
        }
    
    
        private static class Node<E> {
            E item;
            Node<E> next;
            Node<E> prev;
    
            Node(Node<E> prev, E element, Node<E> next) {
                this.item = element;
                this.next = next;
                this.prev = prev;
            }
        }

    add(int index, E e)方法如下,就是在指定位置,把新节点插入到链表,并对应更新其前驱和后续节点的链接关系。

        /**
         * Inserts the specified element at the specified position in this list.
         * Shifts the element currently at that position (if any) and any
         * subsequent elements to the right (adds one to their indices).
         *
         * @param index index at which the specified element is to be inserted
         * @param element element to be inserted
         * @throws IndexOutOfBoundsException {@inheritDoc}
         */
        public void add(int index, E element) {
            //检查索引是否越界
            checkPositionIndex(index);
    
            if (index == size)
                //在链表末端添加新节点
                linkLast(element);
            else
                //在指定位置插入新节点
                linkBefore(element, node(index));
        }
    
    
        private void checkPositionIndex(int index) {
            if (!isPositionIndex(index))
                throw new IndexOutOfBoundsException(outOfBoundsMsg(index));
        }
    
        /**
         * Tells if the argument is the index of a valid position for an
         * iterator or an add operation.
         */
        private boolean isPositionIndex(int index) {
            return index >= 0 && index <= size;
        }
    
        /**
         * Inserts element e before non-null Node succ.
         */
        void linkBefore(E e, Node<E> succ) {
            // assert succ != null;
            //保留要插入节点位置的前驱节点
            final Node<E> pred = succ.prev;
            
            //新建节点
            final Node<E> newNode = new Node<>(pred, e, succ);
            
            //把新建节点作为原节点的前驱节点
            succ.prev = newNode;
            
            //把新建节点作为pred的后续节点,或者作为链表头结点
            if (pred == null)
                first = newNode;
            else
                pred.next = newNode;
            size++;
            modCount++;
        }
        

    get方法如下:

        /**
         * Returns the element at the specified position in this list.
         *
         * @param index index of the element to return
         * @return the element at the specified position in this list
         * @throws IndexOutOfBoundsException {@inheritDoc}
         */
        public E get(int index) {
            //检查索引是否越界
            checkElementIndex(index);
            //根据索引,遍历链表找到数据
            return node(index).item;
        }
    
    
        private void checkElementIndex(int index) {
            if (!isElementIndex(index))
                throw new IndexOutOfBoundsException(outOfBoundsMsg(index));
        }
    
        /**
         * Tells if the argument is the index of an existing element.
         */
        private boolean isElementIndex(int index) {
            return index >= 0 && index < size;
        }
        
        /**
         * Returns the (non-null) Node at the specified element index.
         */
        Node<E> node(int index) {
            // assert isElementIndex(index);
    
            if (index < (size >> 1)) {
                //索引值小于链表总长度的一半,从前往后遍历链表
                Node<E> x = first;
                for (int i = 0; i < index; i++)
                    x = x.next;
                return x;
            } else {
                //索引值大于等于链表总长度的一半,从后往前遍历链表
                Node<E> x = last;
                for (int i = size - 1; i > index; i--)
                    x = x.prev;
                return x;
            }
        }

    根据索引获取元素时,有个小技巧,就是把链表对半分,当索引在前半段时,从前往后遍历,否则反向遍历,该算法可以节省遍历次数,从一半,减为四分之一。

    有个需要注意的地方,Linkedlist里面有两个很相似的方法,一个是获取数据时,检查索引下标是否越界;另外一个是添加数据时,添加位置索引小标是否越界。前者边界条件比后者小1,代码如下:

        /**
         * Tells if the argument is the index of an existing element.
         */
        private boolean isElementIndex(int index) {
            return index >= 0 && index < size;
        }
    
        /**
         * Tells if the argument is the index of a valid position for an
         * iterator or an add operation.
         */
        private boolean isPositionIndex(int index) {
            return index >= 0 && index <= size;
        }

    remove(Object o)函数,该函数从前往后遍历链表,删除第一个满足条件的数据,到此结束。

        /**
         * Removes the first occurrence of the specified element from this list,
         * if it is present.  If this list does not contain the element, it is
         * unchanged.  More formally, removes the element with the lowest index
         * {@code i} such that
         * <tt>(o==null&nbsp;?&nbsp;get(i)==null&nbsp;:&nbsp;o.equals(get(i)))</tt>
         * (if such an element exists).  Returns {@code true} if this list
         * contained the specified element (or equivalently, if this list
         * changed as a result of the call).
         *
         * @param o element to be removed from this list, if present
         * @return {@code true} if this list contained the specified element
         */
        public boolean remove(Object o) {
            if (o == null) {
                for (Node<E> x = first; x != null; x = x.next) {
                    if (x.item == null) {
                        unlink(x);
                        return true;
                    }
                }
            } else {
                for (Node<E> x = first; x != null; x = x.next) {
                    if (o.equals(x.item)) {
                        unlink(x);
                        return true;
                    }
                }
            }
            return false;
        }
    
        /**
         * Unlinks non-null node x.
         */
        E unlink(Node<E> x) {
            // assert x != null;
            final E element = x.item;
            final Node<E> next = x.next;
            final Node<E> prev = x.prev;
            
            //前驱节点解绑,如果前驱节点为空,则后续节点成为first
            if (prev == null) {
                first = next;
            } else {
                prev.next = next;
                x.prev = null;
            }
    
            //后续节点解绑,如果后续节点为空,则前驱节点成为last
            if (next == null) {
                last = prev;
            } else {
                next.prev = prev;
                x.next = null;
            }
    
            //节点数值释放,方便gc回收
            x.item = null;
            size--;
            modCount++;
            return element;
        }

    remove(int index)方法,先检查索引是否越界,然后根据索引获取node,调用unlink方法解绑该节点。

        /**
         * Removes the element at the specified position in this list.  Shifts any
         * subsequent elements to the left (subtracts one from their indices).
         * Returns the element that was removed from the list.
         *
         * @param index the index of the element to be removed
         * @return the element previously at the specified position
         * @throws IndexOutOfBoundsException {@inheritDoc}
         */
        public E remove(int index) {
            checkElementIndex(index);
            return unlink(node(index));
        }
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  • 原文地址:https://www.cnblogs.com/zhangxuezhi/p/11872753.html
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