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  • 迷宫

    // 迷宫2.cpp: 定义控制台应用程序的入口点。
    //

    #include "stdafx.h"
    #include<iostream>
    using namespace std;

    struct stack
    {
    int x;
    int y;
    int d[4];
    stack* next;
    };

    stack* inti()
    {
    stack *s = new stack();
    s->next = NULL;
    for(int i=0;i<4;i++)
    s->d[i] = 0;
    if (!s)
    cout << "error!!!";
    return s;
    }
    //static stack * shorts = inti();

    void push(stack *s, int x, int y)
    {
    stack *t = inti();
    t->x = x;
    t->y = y;
    for(int i=0;i<4;i++)
    t->d[i] = 0;
    t->next = s->next;
    s->next = t;

    }

    stack* pop(stack* s)
    {
    stack* t = inti();
    if (s->next)
    {
    t->x = s->next->x;
    t->y = s->next->y;
    for (int i = 0; i < 4; i++)
    {
    t->d[i]=s->next->d[i];
    }
    stack* n = s->next;
    s->next = n->next;
    delete n;

    }
    else
    cout << "error";
    return t;
    }


    void deletestack(stack* s)
    {
    while (s)
    {
    delete pop(s);
    }
    }

    //计算路径的长度
    int length(stack *s)
    {
    stack * t = s->next;
    int i = 0;
    while (t != NULL)
    {
    t = t->next;
    i++;
    }
    return i;
    }

    //输出路径
    void print(stack *s) //此处经常犯错
    {
    static int stacknum = 0;
    stack *t=s->next;

    //if (length(shorts) > length(s))
    //{
    // deletestack(shorts);
    // while (t != NULL)
    // {
    // push(shorts, t->x, t->y);
    // t = t->next;
    // }
    //}
    /*t = s->next;*/
    cout << "第 "<<++stacknum <<" 个是:" << endl;
    while (t != NULL)
    {
    cout << "(" << t->x << "," << t->y << ")" << endl;
    t = t->next;
    }
    cout << "the length is " << length(s) << endl;
    }

    //最短路径
    //void printshort()
    //{
    // stack * t = shorts->next;
    // while (t)
    // {
    // cout << "(" << t->x << "," << t->y << ") ";
    // t = t->next;
    // }
    //}

    stack * top(stack *s)
    {
    stack *t = pop(s);
    push(s, t->x, t->y);
    return t;
    }


    //打印地图 查看地图出现的变化
    void map(int a[][10])
    {

    for (int i = 0; i < 10; i++)
    {
    for (int j = 0; j < 10; j++)
    {
    cout << a[i][j];
    }
    cout << endl;
    }
    cout << endl;
    //getchar();
    }

    //判断(x,y)周围的路径是否为通
    void is_null(int a[10][10], int x, int y, stack *s)
    {
    if (a[x][y + 1] == 0)
    {
    s->next->d[0] = 1;
    }
    if (a[x + 1][y] == 0)
    {
    s->next->d[1] = 1;
    }
    if (a[x][y - 1] == 0)
    {
    s->next->d[2] = 1;
    }
    if (a[x - 1][y] == 0)
    {
    s->next->d[3] = 1;
    }
    }

    //走迷宫 将路径寄存在栈中
    void zou(int a[10][10], int x, int y, int m, int n, stack*s)
    {

    push(s, x, y);
    a[x][y] = 2;
    /*map(a);*/

    if (x == m && y == n) //走到终点 输出所有路径
    {
    print(s);
    cout << endl;
    /*getchar();*/
    }

    is_null(a, x, y, s); //判断周围的路径是否为通


    //从右到左顺时针递归调用
    if (s->next->d[0] == 1)
    {
    s->next->d[0] = 0;
    zou(a, x, y + 1, m, n, s);
    }
    if (s->next->d[1] == 1)
    {
    s->next->d[1] = 0;
    zou(a, x + 1, y, m, n, s);
    }
    if (s->next->d[2] == 1)
    {
    s->next->d[2] = 0;
    zou(a, x, y - 1, m, n, s);
    }
    if (s->next->d[3] == 1)
    {
    s->next->d[3] = 0;
    zou(a, x - 1, y, m, n, s);
    }


    stack *t =pop(s); //走到尽头 出栈返回上一个周围还有方向的节点
    a[t->x][t->y] = 0; //将走过的节点由2重置为0(未走过)
    //map(a);

    }

    int main()
    {
    stack *s=inti();

    int a[10][10] =//入口 (1,8) 出口 (8,4)
    {
    1,1,1,1,1,1,1,1,1,1,
    1,1,1,1,1,1,0,0,0,1,
    1,1,0,0,0,0,0,0,1,1,
    1,1,0,1,0,1,1,0,1,1,
    1,0,0,0,0,1,1,0,0,1,
    1,1,0,1,0,0,0,0,1,1,
    1,1,0,1,1,0,1,1,0,1,
    1,1,0,1,1,0,1,1,0,1,
    1,1,0,0,0,0,1,0,1,1,
    1,1,1,1,1,1,1,1,1,1
    };
    map(a);
    cout << "please input the entrence and the exit of the maze" << endl;
    int entren_x, entren_y, exit_x, exit_y;
    cout << "please input the entrence's coordinate:";
    cin >> entren_x>>entren_y;
    cout << "please input the exit's coordinate:";
    cin >> exit_x >> exit_y;
    cout << "all way from entrence to exit is :" << endl;
    zou(a, entren_x, entren_y, exit_x, exit_y, s);
    //cout << "the shortest way is:" << endl;
    //printshort();
    cout << "input 'n' to exit:";
    while (getchar() != 'n')
    { }
    return 0;
    }

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  • 原文地址:https://www.cnblogs.com/zhengbao/p/8966153.html
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