n <= 300
结果裸的dfs就直接过了。。
枚举每一层,枚举删除每一层的边,然后把删除的边所连接的子树全部删去
代码
#include <vector>
#include <cstdio>
#include <cstring>
#include <iostream>
#define N 301
#define min(x, y) ((x) < (y) ? (x) : (y))
#define max(x, y) ((x) > (y) ? (x) : (y))
int n, m, cnt, maxd, ans = ~(1 << 31);
int head[N], to[N << 1], next[N << 1], f[N], deep[N], size[N];
std::vector <int> vec[N];
bool vis[N];
inline int read()
{
int x = 0, f = 1;
char ch = getchar();
for(; !isdigit(ch); ch = getchar()) if(ch == '-') f = -1;
for(; isdigit(ch); ch = getchar()) x = (x << 1) + (x << 3) + ch - '0';
return x * f;
}
inline void add(int x, int y)
{
to[cnt] = y;
next[cnt] = head[x];
head[x] = cnt++;
}
inline void dfs(int u)
{
int i, v;
size[u] = 1;
maxd = max(maxd, deep[u] = deep[f[u]] + 1);
vec[deep[u]].push_back(u);
for(i = head[u]; i ^ -1; i = next[i])
{
v = to[i];
if(v ^ f[u])
{
f[v] = u;
dfs(v);
size[u] += size[v];
}
}
}
inline void dfs2(int u, int x)
{
int i, v;
vis[u] = x;
for(i = head[u]; i ^ -1; i = next[i])
{
v = to[i];
if(v ^ f[u]) dfs2(v, x);
}
}
inline void dfs1(int k, int sum)
{
ans = min(ans, n - sum);
if(k == maxd + 1) return;
int i, x;
for(i = 0; i < vec[k].size(); i++)
{
x = vec[k][i];
if(!vis[x])
{
dfs2(x, 1);
dfs1(k + 1, sum + size[x]);
dfs2(x, 0);
}
}
}
int main()
{
int i, x, y;
n = read();
m = read();
memset(head, -1, sizeof(head));
for(i = 1; i <= m; i++)
{
x = read();
y = read();
add(x, y);
add(y, x);
}
dfs(1);
dfs1(2, 0);
printf("%d
", ans);
return 0;
}