[MVC_Json序列化]Json字符串反序列化成C#对象

上一篇中有Json序列化相关问题得到了解决。

那么结果集为Json串时，如何将Json串转成C#对象呢？

现举例说明:

-现有如下字符串数据

string k = "{"rings":["
                +"[[34995.513100000098,4304381.4231000002],[34988.120099999942,4304371.5420999993],"
                + "[34995.513100000098,4304381.4231000002],[34988.120099999942,4304371.5420999993],"
                + "[34995.513100000098,4304381.4231000002],[34988.120099999942,4304371.5420999993]]],"
                + ""spatialReference":";

-想将上面的数据转换成List<point>

public class point {
            public decimal x { get; set; }
            public decimal y { get; set; }
        }

步骤1：

-截取字符串

public string strCutOut(string str) {
            string str1 = str.Substring(str.IndexOf(":[[") + 3, str.IndexOf("]],") - 11);
            string str2 = str1.Replace("],[", "]$[");
            string str3 = str2.Replace("[", "{'x':");
            string str4 = str3.Replace("]", "}");
            string str5 = str4.Replace(",", ",'y':");
            string str6 = str5.Replace("$", ",");
            string str7 = str6.Replace("'", """);
            return str7;
        }

-得到如下字符串

"{"x":34995.513100000098,"y":4304381.4231000002},

{"x":34988.120099999942,"y":4304371.5420999993},

{"x":34995.513100000098,"y":4304381.4231000002},

{"x":34988.120099999942,"y":4304371.5420999993},

{"x":34995.513100000098,"y":4304381.4231000002},

{"x":34988.120099999942,"y":4304371.5420999993}"

步骤2：

-引用System.Runtime.Serialization.Json;

-反序列化字符串

public List<point> convertObject(string json)
        {
            MemoryStream stream2 = new MemoryStream();
            DataContractJsonSerializer ser2 = new DataContractJsonSerializer(typeof(List<point>));
            StreamWriter wr = new StreamWriter(stream2);
            wr.Write(json);
            wr.Flush();
            stream2.Position = 0;
            Object obj = ser2.ReadObject(stream2);
            List<point> list = (List<point>)obj;
            return list;
        }

步骤3：

-调用字符串截取及反序列化字符串

public void readJson(){

            string k = "{"rings":["
                +"[[34995.513100000098,4304381.4231000002],[34988.120099999942,4304371.5420999993],"
                + "[34995.513100000098,4304381.4231000002],[34988.120099999942,4304371.5420999993],"
                + "[34995.513100000098,4304381.4231000002],[34988.120099999942,4304371.5420999993]]],"
                + ""spatialReference":";
            string str = strCutOut(k);
            string json = "[" + str + "]";
            List<point> ls = convertObject(json);
        }

*得到的结果集ls为: