C++ 穷举算法 鸡兔同笼

#include "stdio.h"
int qiongju(int head, int foot, int *chicken, int *rabbit)
{
    int re, i, j;
    re = 0;
    for (i = 0; i <= head; i++)
    {
        j = head - i;
        if (i * 2 + j * 4 == foot)
        {
            re = 1;
            *chicken = i;
            *rabbit = j;
        }
    }
    return re;
}

void main()
{
    int chicken, rabbit, head, foot;
    int re;

    re = qiongju(head,foot,&chicken,&rabbit);

    if (re == 1)
    {
        printf("鸡有：%d 只，兔子有：%d 只。
",chicken,rabbit);
    }
    else 
    {
        printf("无法求解！
");
    }
}

注意变量 re !!!