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  • The 11th Zhejiang Provincial Collegiate Programming Contest->Problem G:G

    http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3782
    题意:把输入的三元运算用计算机运算出来。

     1 #include <bits/stdc++.h>
     2 using namespace std;
     3 int main() {
     4     int t;
     5     cin>>t;
     6     while(t--) {
     7         int a,b,c;
     8         int s1=0;
     9         char n,m;
    10         cin>>a>>n>>b>>m>>c;
    11         if(n=='*'||n=='/'||n=='%') {
    12             if(n=='*')
    13                 s1=a*b;
    14             else if(n=='/')
    15                 s1=a/b;
    16             else
    17                 s1=a%b;
    18             if(m=='*')
    19                 s1=s1*c;
    20             else if(m=='/')
    21                 s1=s1/c;
    22             else if(m=='%')
    23                 s1=(int)s1%c;
    24             else if(m=='+')
    25                 s1=s1+c;
    26             else if(m=='-')
    27                 s1=s1-c;
    28         } else if(m=='*'||m=='/'||m=='%') {
    29             if(m=='*')
    30                 s1=b*c;
    31             else if(m=='/')
    32                 s1=b/c;
    33             else if(m=='%')
    34                 s1=b%c;
    35             if(n=='+')
    36                 s1=a+s1;
    37             else if(n=='-')
    38                 s1=a-s1;
    39 
    40         } else {
    41             if(n=='+')
    42                 s1=a+b;
    43             else if(n=='-')
    44                 s1=a-b;
    45             if(m=='+')
    46                 s1=s1+c;
    47             else if(m=='-')
    48                 s1=s1-c;
    49         }
    50         printf("%d ",s1);
    51 
    52     }
    53     return 0;
    54 }
    我会一直在
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  • 原文地址:https://www.cnblogs.com/zhien-aa/p/5402473.html
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