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  • leetcode题解:Valid Palindrome(判断回文)

    题目:

    Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.

    For example,
    "A man, a plan, a canal: Panama" is a palindrome.
    "race a car" is not a palindrome.

    Note:
    Have you consider that the string might be empty? This is a good question to ask during an interview.

    For the purpose of this problem, we define empty string as valid palindrome.

    说明:

           1)注意两点:a、判断满足条件的字符  b、大写变小写(本题认为不区分大小写)

           2)字符串为空则true

    实现:

     1 class Solution {
     2 public:
     3         bool isPalindrome(string s) {
     4             if(s.empty()) return true;
     5             int len=strlen(s.c_str());
     6             int i=0;
     7             int j=0;
     8             for (;i<len;i++)
     9             {
    10                 if (isChar(s[i]))//去其他符合,若有大写则大写变小写
    11                 {
    12                     s[i] = tolower(s[i]);//库函数
    13                     s[j++]=s[i];
    14                 }
    15             }
    16             s[j]='';
    17             if (s[0]=='') return true;
    18             int len2=strlen(s.c_str());
    19             i=0;
    20             while(i<=len2-1-i) //判断是否回文
    21             {
    22                 if(s[i]!=s[len2-1-i]) return false;
    23                 i++;
    24             }
    25             return true;            
    26     }
    27     private:
    28         bool isChar(char t)//判断是否满足条件字符
    29         {
    30             if (('a' <= t&&t<='z')||('A' <= t&&t<='Z')||('0' <= t&&t<='9'))
    31            {
    32                return true;
    33            }
    34            else
    35                return false;           
    36         }
    37 };
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  • 原文地址:https://www.cnblogs.com/zhoutaotao/p/3829994.html
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