zoukankan      html  css  js  c++  java
  • C# 判断两个集合(List)是否相等

    1.两个list如果有重复元素(如List1: a,b,a  List2: b,b,a) 是无法通过包含关系来判断是否相等的.

    有两个办法,其一是两个List排序后再按顺序比较.另一个办法就是计算各元素的重复项再进行比较

    第一种方案劣势太明显,时间复杂度过大

    第二种以空间换时间,只需要遍历无需排序即可.

            /// <summary>
            /// 判断两个集合是否是相等的(所有的元素及数量都相等)
            /// </summary>
            /// <typeparam name="T">集合元素类型</typeparam>
            /// <param name="sourceCollection">源集合列表</param>
            /// <param name="targetCollection">目标集合列表</param>
            /// <returns>两个集合相等则返回True,否则返回False</returns>
            public static bool EqualList<T>(this IList<T> sourceCollection, IList<T> targetCollection) where T : IEquatable<T>
            {
                //空集合直接返回False,即使是两个都是空集合,也返回False
                if (sourceCollection == null || targetCollection == null)
                {
                    return false;
                }
    
                if (object.ReferenceEquals(sourceCollection, targetCollection))
                {
                    return true;
                }
    
                if (sourceCollection.Count != targetCollection.Count)
                {
                    return false;
                }
    
                var sourceCollectionStaticsDict = sourceCollection.StatisticRepetition();
                var targetCollectionStaticsDict = targetCollection.StatisticRepetition();
    
                return sourceCollectionStaticsDict.EqualDictionary(targetCollectionStaticsDict);
            }
    
            /// <summary>
            /// 判断两个字典是否是相等的(所有的字典项对应的值都相等)
            /// </summary>
            /// <typeparam name="TKey">字典项类型</typeparam>
            /// <typeparam name="TValue">字典值类型</typeparam>
            /// <param name="sourceDictionary">源字典</param>
            /// <param name="targetDictionary">目标字典</param>
            /// <returns>两个字典相等则返回True,否则返回False</returns>
            public static bool EqualDictionary<TKey, TValue>(this Dictionary<TKey, TValue> sourceDictionary, Dictionary<TKey, TValue> targetDictionary)
                where TKey : IEquatable<TKey>
                where TValue : IEquatable<TValue>
            {
                //空字典直接返回False,即使是两个都是空字典,也返回False
                if (sourceDictionary == null || targetDictionary == null)
                {
                    return false;
                }
    
                if (object.ReferenceEquals(sourceDictionary, targetDictionary))
                {
                    return true;
                }
    
                if (sourceDictionary.Count != targetDictionary.Count)
                {
                    return false;
                }
    
                //比较两个字典的Key与Value
                foreach (var item in sourceDictionary)
                {
                    //如果目标字典不包含源字典任意一项,则不相等
                    if (!targetDictionary.ContainsKey(item.Key))
                    {
                        return false;
                    }
    
                    //如果同一个字典项的值不相等,则不相等
                    if (!targetDictionary[item.Key].Equals(item.Value))
                    {
                        return false;
                    }
                }
    
                return true;
            }
    
            /// <summary>
            /// 统计集合的重复项,并返回一个字典
            /// </summary>
            /// <typeparam name="T">集合元素类型</typeparam>
            /// <param name="sourceCollection">统计集合列表</param>
            /// <returns>返回一个集合元素及重复数量的字典</returns>
            private static Dictionary<T, int> StatisticRepetition<T>(this IEnumerable<T> sourceCollection) where T : IEquatable<T>
            {
                var collectionStaticsDict = new Dictionary<T, int>();
                foreach (var item in sourceCollection)
                {
                    if (collectionStaticsDict.ContainsKey(item))
                    {
                        collectionStaticsDict[item]++;
                    }
                    else
                    {
                        collectionStaticsDict.Add(item, 1);
                    }
                }
    
                return collectionStaticsDict;
            }

    2

     public class CommonTest  
        {
            /// <summary>
            /// 集合相等比较
            /// </summary>
            [Fact]
            public void ListEqual_Tests()
            {
                var sourceList = new List<string>()
                {
                    "a",
                    "b",
                    "a"
                };
    
                var targetList = new List<string>()
                {
                    "b",
                    "b",
                    "a"
                };
    
                var resp = sourceList.EqualList(targetList);
                Assert.False(resp );
            }
    
            /// <summary>
            /// 集合相等比较
            /// </summary>
            [Fact]
            public void ListEqual2_Tests()
            {
                var sourceList = new List<string>()
                {
                    "a",
                    "b",
                };
    
                var targetList = new List<string>()
                {
                    "b",
                    "a"
                };
    
                var resp = sourceList.EqualList(targetList);
                Assert.True(resp);
            }
        }
  • 相关阅读:
    Phonics 自然拼读法 s,a,t,i,p,n Teacher:Lamb
    English Voice of <<City of stars>>
    English trip EM2-LP-1A Hi Teacher:Taylor
    English trip EM2-PE-6B Teacher:Taylor,Patrick(2019.12.2)
    English trip EM2-PE-6A Family Relationship Teacher:Taylor
    keras各种优化方法总结 SGDmomentumnesterov
    keras做DNN
    keras、 tensor flow 教程
    DNN例子
    tensor flow 的两种padding方式
  • 原文地址:https://www.cnblogs.com/zhshlimi/p/8418903.html
Copyright © 2011-2022 走看看