while练习

# 作业（必做题）：
#1. 使用while循环输出1 2 3 4 5 6     8 9 10

cout = 1
while cout < 10:
    cout += 1
    if cout == 7:
        continue
    print(cout,end=" ")
print("")

#2. 求1-100的所有数的和

cout = 0
c_sum = 0
while cout < 100:
    cout += 1
    c_sum += cout
print(c_sum)

#3. 输出 1-100 内的所有奇数

cout = 1
while cout <= 100:
    if cout % 2 == 1:
        print(cout,end=" ")
    cout += 1
print("")

#4. 输出 1-100 内的所有偶数

cout = 1
while cout <= 100:
    if cout % 2 == 0:
        print(cout,end=" ")
    cout += 1
print("")

#5. 求1-2+3-4+5 ... 99的所有数的和

cout = 1
c_sum = 0
while cout < 100:
    if cout % 2 == 0:
        c_sum -= cout
    else:
        c_sum += cout
    cout += 1
print(c_sum)

#6. 用户登陆（三次机会重试）

name_data = {"Jil":1118, "Fishball":188741}
cout = 0
while cout < 3:
    name = input("Please input your username：")
    psw = input("Please input your password：")

    if name in name_data and psw == name_data.get(name):
        print("Congratulation！Log in!")
        break
    else:
        print("Account number or password error, login failed!")
        cout += 1
else:
    print("3 times error!bang!")

#7：猜年龄游戏
    # 要求：
    # 允许用户最多尝试3次，3次都没猜对的话，就直接退出，如果猜对了，打印恭喜信息并退出

cout = 0
s_age = 15
while cout < 3:
    age = input("Please input your guessing age：")
    if age == s_age:
        print("Bingo！")
        break
    else:
        print("Wrong number!")
        cout += 1

#8：猜年龄游戏升级版（选做题）
# 要求：
#     允许用户最多尝试3次
#     每尝试3次后，如果还没猜对，就问用户是否还想继续玩，如果回答Y或y, 就继续让其猜3次，以此往复，如果回答N或n，就退出程序
#     如何猜对了，就直接退出

import random
guess_age = random.randint(0,150)
cout = 0
tag = True
while tag:
    while cout < 3:
        age = input("Please input your guessing number:")
        if age.isdigit():
            if int(age) < guess_age:
                print("think bigger!")
                cout += 1
            elif int(age) > guess_age:
                print("think smaller!")
                cout += 1
            else:
                print("Bingo！")
                Tag = False
                break
        else:
            print("Please input integer!")
    else:
        flag = input("Continue?(Y/N)")
        if flag =="Y" or flag == "y":
            cout = 0
        elif flag == 'N' or flag == 'n':
            tag = False                           #
        else:
            print("Wrong input！Try again！")