在页面上异步获取Controller中响应的json数据。
<%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%> <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>User List</title> <script type="text/javascript" src="${pageContext.request.contextPath}/resource/script/jquery-1.9.1.min.js"></script> <script type="text/javascript"> $(document).ready(function(){ $("#button_getUser").click(function(){ //异步请求json数据 $.ajax({ type:"POST", url:"${pageContext.request.contextPath}/user/getUserList", success:function(data){ //迭代返回的json数据 $.each(data,function(i,user){ $("#results").append(user.userName+"---"+user.password+"<br>"); }); }, error:function(e) { alert("出错："+e); } }); }); }); </script> </head> <body> <input type="button" id="button_getUser" value="获取用户列表"><br> 用户信息：<br> <div id="results"> </div> </body> </html> Controller中的代码： @RequestMapping("/getUserList") public String getUserList(HttpServletResponse response) { response.setCharacterEncoding("UTF-8"); response.setContentType("application/json"); List<User> userList = getUsers(); Gson gson = new Gson(); String json = gson.toJson(userList); System.out.println("json---"+json); PrintWriter out = null; try { out = response.getWriter(); out.write(json); out.flush(); }catch(Exception e) { e.printStackTrace(); }finally { if(out != null) { out.close(); } } return "/user/userList"; } private List<User> getUsers() { List<User> users = new ArrayList<User>(); User user1 = new User(); user1.setUserName("李坏"); user1.setPassword("LiHuai"); User user2 = new User(); user2.setUserName("阿飞"); user2.setPassword("aFei"); User user3 = new User(); user3.setUserName("陆小凤"); user3.setPassword("LuXiaoFeng"); users.add(user1); users.add(user2); users.add(user3); return users; }
或者使用@ResponseBody，需要用到jackson相关的包。