Careercup

2014-05-11 02:56

题目链接

原题：

Write a function called FooBar that takes input integer n and prints all the numbers from 1 upto n in a new line. If the number is divisible by 3 then print "Foo", if the number is divisible by 5 then print "Bar" and if the number is divisible by both 3 and 5, print "FooBar". Otherwise just print the number. 
for example FooBar(15) should print as follows: 
1 
2 
Foo 
4 
Bar 
Foo 
7 
8 
Foo 
Bar 
11 
Foo 
13 
14 
FooBar 

I know, easy right? ;)

题目：从1到n的整数，如果被3整除就输出Foo，如果被5整除就输出Bar，如果是公倍数就输出FooBar，否则直接输出原数。

解法：这题有什么陷阱？n可以是大数吗？n可以小于1吗？如果是实际面试，肯定要问清楚的。在此，我就按最简单的处理了。在这种题目上自找麻烦是没意义的。

代码：

// http://www.careercup.com/question?id=6543214668414976
#include <iostream>
#include <sstream>
using namespace std;

int main()
{
    int n;
    int i;
    
    while (cin >> n && n > 0) {
        for (i = 1; i <= n; ++i) {
            if (i % 3) {
                if (i % 5) {
                    cout << i;
                } else {
                    cout << "Bar";
                }
            } else {
                if (i % 5) {
                    cout << "Foo";
                } else {
                    cout << "FooBar";
                }
            }
            cout << endl;
        }
    }
    
    return 0;
}