/*
* 线段树模板
* 区间修改 区间查询
* 版本一:当前区间值正确,tag未下传
*/
#include<iostream>
#include<cstdio>
#include<queue>
#include<algorithm>
#include<cstring>
using namespace std;
typedef long long LL;
const int MAXN=1e6+5;
const LL INF=2e18;
//const int INF=0x3f3f3f3f;//根据是否超long long修改
LL a[MAXN];
//线段树节点结构体
struct Node{
int left,right;//左右边界
LL mi,ma;//最小值 最大值
LL sum;//和
LL add;//增减标记
int set;//重置标记
}tree[MAXN*4];//空间开四倍
//向上更新
void PushUp(int rt){
int lson=rt<<1,rson=rt<<1|1; //rt << 1 | 1 等价与 rt * 2 + 1
tree[rt].mi=min(tree[lson].mi,tree[rson].mi);
tree[rt].ma=max(tree[lson].ma,tree[rson].ma);
tree[rt].sum=tree[lson].sum+tree[rson].sum;
}
//向下传递标记
void PushDown(int rt){
if(tree[rt].left<tree[rt].right){//如果不是叶子
int lson=rt<<1,rson=rt<<1|1;
if(tree[rt].set!=-1){//set初始为一个不会重置到的数,这里是-1
tree[lson].set=tree[rt].set;tree[rson].set=tree[rt].set;
tree[lson].add=tree[rson].add=0;//add失效
tree[lson].mi=tree[rson].mi=tree[rt].set;
tree[lson].ma=tree[rson].ma=tree[rt].set;
tree[lson].sum=(LL)tree[rt].set*(tree[lson].right-tree[lson].left+1);
tree[rson].sum=(LL)tree[rt].set*(tree[rson].right-tree[rson].left+1);
tree[rt].set=-1;
}
if(tree[rt].add){
tree[lson].add+=tree[rt].add; tree[rson].add+=tree[rt].add;
tree[lson].mi+=tree[rt].add; tree[rson].mi+=tree[rt].add;
tree[lson].ma+=tree[rt].add; tree[rson].ma+=tree[rt].add;
tree[lson].sum+=(LL)tree[rt].add*(tree[lson].right-tree[lson].left+1);
tree[rson].sum+=(LL)tree[rt].add*(tree[rson].right-tree[rson].left+1);
tree[rt].add=0;
}
}
}
//建立函数
void Build(int rt,int L,int R){
tree[rt].left=L;tree[rt].right=R;tree[rt].add=0;tree[rt].set=-1;
if(L==R) {
tree[rt].sum=tree[rt].mi=tree[rt].ma=a[L];
return;
}
int mid=(tree[rt].left+tree[rt].right)>>1;
Build(rt<<1,L,mid);//只有Build时LR才会变
Build(rt<<1|1,mid+1,R);
PushUp(rt);
}
LL QuerySum(int rt,int L,int R){
if(R<tree[rt].left||L>tree[rt].right) return 0;
if(L<=tree[rt].left&&tree[rt].right<=R)
return tree[rt].sum;
PushDown(rt);
int mid=(tree[rt].left+tree[rt].right)>>1;
LL res=0;
if(L<=mid) res+=QuerySum(rt<<1,L,R);
if(R>mid) res+=QuerySum(rt<<1|1,L,R);
PushUp(rt);
return res;
}
LL QueryMin(int rt,int L,int R){
if(L<=tree[rt].left&&tree[rt].right<=R) return tree[rt].mi;
PushDown(rt);
int mid=(tree[rt].left+tree[rt].right)>>1;
LL res=INF;
if(L<=mid) res=min(res,QueryMin(rt<<1,L,R));
if(R>mid) res=min(res,QueryMin(rt<<1|1,L,R));
PushUp(rt);
return res;
}
LL QueryMax(int rt,int L,int R){
if(L<=tree[rt].left&&tree[rt].right<=R) return tree[rt].ma;//完全包含才产生贡献
PushDown(rt);
int mid=(tree[rt].left+tree[rt].right)>>1;
LL res=-INF;
if(L<=mid) res=max(res,QueryMax(rt<<1,L,R));
if(R>mid) res=max(res,QueryMax(rt<<1|1,L,R));
PushUp(rt);
return res;
}
void UpdateAdd(int rt,int L,int R,int x){//把区间[L,R]加上x
if(L<=tree[rt].left&&tree[rt].right<=R){
tree[rt].add+=x;
tree[rt].sum+=(LL)x*(tree[rt].right-tree[rt].left+1);
tree[rt].mi+=x;tree[rt].ma+=x;
return;
}
PushDown(rt);
int mid=(tree[rt].left+tree[rt].right)>>1;
if(L<=mid) UpdateAdd(rt<<1,L,R,x);
if(R>mid) UpdateAdd(rt<<1|1,L,R,x);
PushUp(rt);
}
void Display(int rt){
cout<<"-------------"<<endl;
cout<<"id: "<<rt<<endl;
cout<<"["<<tree[rt].left<<","<<tree[rt].right<<"]"<<endl;
cout<<"mi: "<<tree[rt].mi<<endl;
cout<<"ma: "<<tree[rt].ma<<endl;
cout<<"sum: "<<tree[rt].sum<<endl;
cout<<"add: "<<tree[rt].add<<endl;
cout<<"set: "<<tree[rt].set<<endl;
}
void bfs(int rt){
queue<int> q;
while(!q.empty()) q.pop();
q.push(rt);
while(!q.empty()){
int fst=q.front();
q.pop();
Display(fst);
if(tree[fst].right>tree[fst].left){
q.push(fst<<1);
q.push(fst<<1|1);
}
}
}
void UpdateSet(int rt,int L,int R,int x){//把区间[x,y]置为x
if(L<=tree[rt].left&&tree[rt].right<=R){
tree[rt].set=x;
tree[rt].sum=(LL)x*(tree[rt].right-tree[rt].left+1);
tree[rt].mi=x;tree[rt].ma=x;
tree[rt].add=0;
return;
}
PushDown(rt);
int mid=(tree[rt].left+tree[rt].right)>>1;
if(L<=mid) UpdateSet(rt<<1,L,R,x);
if(R>mid){
UpdateSet(rt<<1|1,L,R,x);
}
PushUp(rt);
}
int main(){
int n,m;//n个数 m次询问
while(scanf("%d%d",&n,&m)!=EOF){
for(int i=1;i<=n;i++) scanf("%lld",&a[i]);
Build(1,1,n);//建立线段树
int op,x,y,z;
for(int i=1;i<=m;i++){
scanf("%d%d%d",&op,&x,&y);
if(op==1){//询问[x,y]的和,求平均值可以直接求和然后处以总个数
printf("Case #%d:
",i);
printf("%lld
",QuerySum(1,x,y));
}else if(op==2){//询问[x,y]的最大值
printf("Case #%d:
",i);
printf("%lld
",QueryMax(1,x,y));
}else if(op==3){//询问[x,y]的最小值
printf("Case #%d:
",i);
printf("%lld
",QueryMin(1,x,y));
}else if(op==4){//在[x,y]区间加上z
scanf("%d",&z);
UpdateAdd(1,x,y,z);
}else{//把[x,y]重置为z
scanf("%d",&z);
UpdateSet(1,x,y,z);
}
}
}
return 0;
}