A1031. Hello World for U

Given any string of N (>=5) characters, you are asked to form the characters into the shape of U. For example, "helloworld" can be printed as:

h  d
e  l
l  r
lowo

That is, the characters must be printed in the original order, starting top-down from the left vertical line with n₁ characters, then left to right along the bottom line with n₂ characters, and finally bottom-up along the vertical line with n₃ characters. And more, we would like U to be as squared as possible -- that is, it must be satisfied that n₁ = n₃ = max { k| k <= n₂ for all 3 <= n₂ <= N } with n₁ + n₂ + n₃ - 2 = N.

Input Specification:

Each input file contains one test case. Each case contains one string with no less than 5 and no more than 80 characters in a line. The string contains no white space.

Output Specification:

For each test case, print the input string in the shape of U as specified in the description.

Sample Input:

helloworld!

Sample Output:

h   !
e   d
l   l
lowor

#include<cstdio>
#include<iostream>
#include<string.h>
using namespace std;
int main(){
    char str[81], print[30][30];
    int len, n1, n2, n3;
    for(int i = 0; i < 30; i++)
        for(int j = 0; j < 30; j++)
            print[i][j] = ' ';
    scanf("%s", str);
    len = strlen(str);
    n1 = n3 = (len + 2) / 3;
    n2 = len + 2 - n1 - n3;
    int i;
    for(i = 0; i < n1; i++){
        print[i][0] = str[i];
    }
    for(int j = 1; j < n2; j++, i++){
        print[n1 - 1][j] = str[i];
    }
    for(int k = n1 - 2; k >= 0; k--, i++){
        print[k][n2 - 1] = str[i];
    }
    for(int j = 0; j < n1; j++){
        for(int k = 0; k < n2; k++)
            printf("%c", print[j][k]);
        printf("
");
    }
    cin >> i;
    return 0;

}

总结：

1、打印输出题两种方法，先将其处理在二维字符数组中再逐行输出。或者直接按规律打印输出。根据题意找规律很重要。

2、涉及到字符数组处理时可以使用string.h