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  • BZOJ 3511 土地划分

    随便建个最小割啦。。。

    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    #include<queue>
    #define maxv 50050
    #define maxe 500050
    #define inf 0x7f7f7f7f7f7f7f7fLL
    using namespace std;
    long long n,m,vala[maxv],valb[maxv],sum=0,max_flow=0,x,y,a,b,c,s=1,t,nume=1,g[maxv];
    long long dis[maxv];
    struct edge
    {
        long long v,f,nxt;
    }e[maxe];
    queue <long long> q;
    void addedge(long long u,long long v,long long f)
    {
        e[++nume].v=v;e[nume].f=f;
        e[nume].nxt=g[u];g[u]=nume;
        e[++nume].v=u;e[nume].f=0;
        e[nume].nxt=g[v];g[v]=nume;
    }
    bool bfs()
    {
        for (long long i=s;i<=t;i++) dis[i]=inf;
        dis[s]=0;q.push(s);
        while (!q.empty())
        {
            long long head=q.front();q.pop();
            for (long long i=g[head];i;i=e[i].nxt)
            {
                long long v=e[i].v;
                if ((e[i].f>0) && (dis[v]>dis[head]+1))
                {
                    dis[v]=dis[head]+1;
                    q.push(v);
                }
            }
        }
        return dis[t]!=inf;
    }
    long long dinic(long long x,long long low)
    {
        if (x==t) return low;
        long long ret=0;
        for (long long i=g[x];low && i;i=e[i].nxt)
        {
            long long v=e[i].v;
            if ((e[i].f>0) && (dis[v]==dis[x]+1))
            {
                long long dd=dinic(v,min(low,e[i].f));
                ret+=dd;low-=dd;
                e[i].f-=dd;e[i^1].f+=dd;
            }
        }
        if (!ret) dis[x]=inf;
        return ret;
    }
    int main()
    {
        scanf("%lld%lld",&n,&m);t=n;
        for (long long i=2;i<=n-1;i++) {scanf("%lld",&vala[i]);sum+=vala[i];vala[i]<<=1;}
        for (long long i=2;i<=n-1;i++) {scanf("%lld",&valb[i]);sum+=valb[i];valb[i]<<=1;}
        for (long long i=1;i<=m;i++)
        {
            scanf("%lld%lld%lld%lld%lld",&x,&y,&a,&b,&c);sum+=a+b;
            if (x>y) swap(x,y);
            if ((x==1) && (y==n))
            {
                sum-=a+b+c;
                continue;
            }
            if (x==1) vala[y]+=2*a+2*c,sum-=b;
            else if (y==n) valb[x]+=2*b+2*c,sum-=a;
            else vala[x]+=a,valb[x]+=b,vala[y]+=a,valb[y]+=b;
            if ((x!=1) && (y!=n)) addedge(x,y,a+b+2*c),addedge(y,x,a+b+2*c);
        }
        for (long long i=2;i<=n-1;i++) addedge(s,i,vala[i]),addedge(i,t,valb[i]);
        while (bfs())
            max_flow+=dinic(s,inf);
        printf("%lld
    ",sum-max_flow/2);
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/ziliuziliu/p/6428360.html
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