zoukankan      html  css  js  c++  java
  • BZOJ 2153 设计铁路

    裸的斜率优化。

    (我为什么要O(1e6)。。。)

    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    #define maxn 1000050
    using namespace std;
    long long n,m,t,r,sum1[maxn],sum2[maxn],f[maxn],mx=0,q[maxn],l=1;
    long long get_x(long long x) {return x;}
    long long get_y(long long x)
    {
        if (!x) return 0;
        return f[x-1]-sum1[x-1]+sum2[x-1]*x+m;
    }
    int main()
    {
        scanf("%lld%lld",&n,&m);
        for (long long i=1;i<=n;i++)
        {
            scanf("%lld%lld",&t,&r);
            mx=max(mx,t);sum1[t]+=r*t;sum2[t]+=r;
        }
        for (long long i=1;i<=mx;i++) sum1[i]+=sum1[i-1],sum2[i]+=sum2[i-1];
        q[l=r=1]=0;
        for (long long i=1;i<=mx;i++)
        {
            while (l<r && (get_x(q[r-1])-get_x(q[r]))*(get_y(q[r])-get_y(i))<(get_x(q[r])-get_x(i))*(get_y(q[r-1])-get_y(q[r]))) r--;
            q[++r]=i;
            while (l<r && sum2[i]*(get_x(q[l])-get_x(q[l+1]))<(get_y(q[l])-get_y(q[l+1]))) l++;
            f[i]=get_y(q[l])-q[l]*sum2[i]+sum1[i];f[i]=min(f[i],sum1[i]);
        }
        printf("%lld
    ",f[mx]);
        return 0;
    }
  • 相关阅读:
    倒计时2(小于0时的格式)
    日期 Date()
    倒计时5(超过时间为0:0:0)
    倒计时4
    倒计时3
    Lucene_solr
    Solr与tomcat搭建(搭建好)
    SSM(Spring-SpringMvc-Mybatis)练习
    SpringMvc
    Mybatis(使用)与Spring整合
  • 原文地址:https://www.cnblogs.com/ziliuziliu/p/6669579.html
Copyright © 2011-2022 走看看