C语言最简单的双向链表源码

#include <stdio.h>
#include <stdlib.h>

typedef struct node
{
    char        name[20];
    struct node    *prior, *next;
} stud;


stud* creat( int n )
{
    stud    *p, *h, *s;
    int    i;
    h        = (stud *) malloc( sizeof(stud) );
    h->name[0]    = '';
    h->prior    = NULL;
    h->next        = NULL;
    p        = h;

    for ( i = 0; i < n; i++ )
    {
        s    = (stud *) malloc( sizeof(stud) );
        p->next = s;
        printf( "输入第个%d学生的姓名：", i + 1 );
        scanf( "%s", s->name );
        s->prior    = p;
        s->next        = NULL;
        p        = s;
    }

    p->next = NULL;
    return(h);
}


stud * search( stud *h, char * x )
{
    stud    *p;
    char    *y;
    p = h->next;
    while ( p )
    {
        y = p->name;
        if ( strcmp( y, x ) == 0 )
            return(p);
        else
            p = p->next;
    }
    printf( "没有找到数据
" );
}


void del( stud *p )
{
    p->next->prior    = p->prior;
    p->prior->next    = p->next;
    free( p );
}


void main()
{
    int    number;
    char    sname[20];
    stud    *head, *sp;
    puts( "请输入链表的大小：" );
    scanf( "%d", &number );
    head    = creat( number );
    sp    = head->next;
    printf( "
现在这个双向链表是：
" );
    while ( sp )
    {
        printf( "%s ", &*(sp->name) );
        sp = sp->next;
    }
    printf( "
请输入你想查找的姓名：
" );
    scanf( "%s", sname );
    sp = search( head, sname );
    printf( "你想查找的姓名是:%s
", &*(sp->name) );
    del( sp );
    sp = head->next;
    printf( "
现在这个双向链表是：
" );
    while ( sp )
    {
        printf( "%s ", &*(sp->name) );
        sp = sp->next;
    }
    printf( "
" );
    puts( "
请按任意键退出..." );
}