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  • PHP PDO小试 PHP

    网上关于PDO的资料很多。这里就不累赘了。

    这里我将PDO所有操作封装到一个类里方便操作。

    类代码如下:

    class DB {
    	
    	//pdo对象
    	public $con = NULL;
    	
    	function DB()
    	{
    		$this->con = new PDO("mysql:host=127.0.0.1;dbname=dbtest", "root", "xxx", array(
    			PDO::MYSQL_ATTR_INIT_COMMAND => 'SET NAMES `utf8`',
    			PDO::ATTR_PERSISTENT => TRUE,
    		));
    		
    		$this->con->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
    		$this->con->setAttribute(PDO::ATTR_CASE, PDO::CASE_UPPER);
    	}
    	
    	public function query($sql, $para = NULL)
    	{
    		$sqlType = strtoupper(substr($sql, 0, 6));
    		
    		$cmd = $this->con->prepare($sql);
    		if($para != NULL)
    		{
    			$cmd->execute($para);
    		}
    		else
    		{
    			$cmd->execute();
    		}
    		
    		if($sqlType == "SELECT")
    		{
    			return $cmd->fetchAll();	
    		}
    		
    		if($sqlType == "INSERT")
    		{
    			return $this->con->lastInsertId();
    		}
    		
    		return $cmd->rowCount();
    	}
    }
    

    使用方法:

    include "pdo.php";
    
    $db = new DB();
    $subjectList = $db->query("SELECT * FROM `table1`");
    $count = $db->query("UPDATE `table1` SET `name` = 'test' WHERE `id` = :id", array(':id' => 795));
    
    try
    {
    	echo $db->con->beginTransaction();
    	$count = $db->con->exec("UPDATE `table1` SET `name` = 'test1' WHERE `id` = 795");
    	$count = $db->con->exec("UPDATE `table1` SET `name1` = 'test22' WHERE `id` = 795");
    	$count = $db->con->exec("UPDATE `table1` SET `name1` = 'test333' WHERE `id` = 795");
    	echo $db->con->commit();
    }
    catch (Exception $e)
    {
    	// MYSQL 的表类型 InnoDB(支持事务) MyISAM(不支持事务)
    	echo $db->con->rollBack();
    	throw new MyException("事务测试错误", $e);
    }
    
    $db = NULL;
    

    PDO支持SQL语句以参数方式调用,可有效的防止SQL注入。

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  • 原文地址:https://www.cnblogs.com/zjfree/p/2934272.html
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