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  • C# 小数位数保留的方法集锦

    1.System.Globalization.NumberFormatInfo provider = new System.Globalization.NumberFormatInfo();
    provider.NumberDecimalDigits =intDecLength; //要设定的小数位数
    double strCashAmt=Convert.ToDouble(this.txtCashAmt.Text); //先把控件內的值转成double
    this.txtCashAmt.Text = strCashAmt.ToString("N",provider); //再利用ToString函数格式化小数位数
    2.保留N位,四舍五入 .
    decimal d= decimal.Round(decimal.Parse("0.55555"),2);
    3.保留N位四舍五入
    Math.Round(0.55555,2)
    4,保留N位四舍五入
    double dbdata = 0.55555;
    string str1 = dbdata.ToString("f2");//fN 保留N位,四舍五入
    5.保留N位四舍五入
    string result = String.Format("{0:N2}", 0.55555);//2位
    string result = String.Format("{0:N3}", 0.55555);//3位
    6. 保留N位四舍五入 (不错)
    double s=0.55555;
    result=s.ToString("#0.00");//点后面几个0就保留几位

    C#下如果显示保留小数位数,及百分号的解决方法:
    1、用NumberFormatInfo类来解决:
    System.Globalization.NumberFormatInfo provider = new System.Globalization.NumberFormatInfo();
    provider.PercentDecimalDigits = 2;//小数点保留几位数.
    provider.PercentPositivePattern = 2;//百分号出现在何处.
    double result = (double)1 / 3;//一定要用double类型.
    Response.Write(result.ToString("P", provider));
    2、用toString方法.:
    public string getRate(double hcount, double task)
    {
    string rValue;
    string temp = "";
    if (task == 0)
    {
    task = 1;
    }
    double db = (hcount / task) * 100;
    if (hcount >= task)
    {
    rValue = "100%";
    }
    else
    {
    rValue = db.ToString("#0.#0") + "%";
    }
    return rValue;
    }
    string str1 = String.Format("{0:N1}",56789); //result: 56,789.0
    string str2 = String.Format("{0:N2}",56789); //result: 56,789.00
    string str3 = String.Format("{0:N3}",56789); //result: 56,789.000
    string str8 = String.Format("{0:F1}",56789); //result: 56789.0
    string str9 = String.Format("{0:F2}",56789); //result: 56789.00
    string str11 =(56789 / 100.0).ToString("#.##"); //result: 567.89
    string str12 =(56789 / 100).ToString("#.##"); //result: 567

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  • 原文地址:https://www.cnblogs.com/zjoch/p/1706381.html
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