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  • 200. Number of Islands(DFS)

    Given a 2d grid map of '1's (land) and '0's (water), count the number of islands. An island is surrounded by water and is formed by connecting adjacent lands horizontally or vertically. You may assume all four edges of the grid are all surrounded by water.

    Example 1:

    Input:
    11110
    11010
    11000
    00000
    
    Output: 1
    

    Example 2:

    Input:
    11000
    11000
    00100
    00011
    
    Output: 3



    遇到1 ,就dfs 吃掉他的邻居。

     1 class Solution {
     2 public:
     3     int numIslands(vector<vector<char>>& grid) {
     4         if(grid.size()==0) return 0;
     5         int cnt =0;
     6         for(int i =0;i<grid.size();i++)
     7             for(int j = 0;j <grid[0].size();j++){
     8                 cnt+=grid[i][j]-'0';
     9                 dfs(grid,i,j);
    10             }
    11         return cnt;   
    12     }
    13     void dfs(vector<vector<char>>& grid,int x,int y ){
    14         if(x>= grid.size()||y>=grid[0].size()||x<0||y<0||grid[x][y]=='0') return ;
    15         grid[x][y] = '0';
    16         dfs( grid,x-1,y);
    17         dfs( grid,x+1,y);
    18         dfs( grid,x,y-1);
    19         dfs( grid,x,y+1);
    20     }
    21 };

    http://zxi.mytechroad.com/blog/searching/leetcode-200-number-of-islands/

    
    
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  • 原文地址:https://www.cnblogs.com/zle1992/p/10289487.html
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