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  • 437. Path Sum III(路径可以任意点开始,任意点结束)



    You are given a binary tree in which each node contains an integer value.

    Find the number of paths that sum to a given value.

    The path does not need to start or end at the root or a leaf, but it must go downwards (traveling only from parent nodes to child nodes).

    The tree has no more than 1,000 nodes and the values are in the range -1,000,000 to 1,000,000.

    Example:

    root = [10,5,-3,3,2,null,11,3,-2,null,1], sum = 8
    
          10
         /  
        5   -3
       /     
      3   2   11
     /    
    3  -2   1
    
    Return 3. The paths that sum to 8 are:
    
    1.  5 -> 3
    2.  5 -> 2 -> 1
    3. -3 -> 11



     1 class Solution {
     2 
     3     public int pathSum(TreeNode root, int sum) {
     4         if(root==null) return 0;
     5          int res = path(root,sum)+pathSum(root.right,sum)+pathSum(root.left,sum);
     6         return res;
     7         
     8     }
     9      
    10     private int path(TreeNode root, int sum) {
    11         int res=0;
    12         if(root==null)
    13             return res ;
    14         if(sum==root.val)
    15             res+=1;
    16         res+=path(root.left,sum-root.val);
    17         res+=path(root.right,sum-root.val);
    18         return res;
    19     }
    20       
    21 }
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  • 原文地址:https://www.cnblogs.com/zle1992/p/7842810.html
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