zoukankan      html  css  js  c++  java
  • 1041 Be Unique (20 分)

    1041 Be Unique (20 分)
     

    Being unique is so important to people on Mars that even their lottery is designed in a unique way. The rule of winning is simple: one bets on a number chosen from [1]. The first one who bets on a unique number wins. For example, if there are 7 people betting on { 5 31 5 88 67 88 17 }, then the second one who bets on 31 wins.

    Input Specification:

    Each input file contains one test case. Each case contains a line which begins with a positive integer N (≤) and then followed by N bets. The numbers are separated by a space.

    Output Specification:

    For each test case, print the winning number in a line. If there is no winner, print None instead.

    Sample Input 1:

    7 5 31 5 88 67 88 17
    

    Sample Output 1:

    31
    

    Sample Input 2:

    5 888 666 666 888 888
    

    Sample Output 2:

    None

    应该没有比这更简单的题了
     
     
     1 #include <bits/stdc++.h>
     2 
     3 using namespace std;
     4 int n;
     5 int an[100005];
     6 int vis[10005];
     7 int main(){
     8     cin >> n;
     9     for(int i = 0; i<n; i++){
    10         cin >> an[i];
    11         vis[an[i]]++;
    12     }
    13     for(int i = 0; i < n; i++){
    14         if(vis[an[i]] == 1){
    15             cout << an[i] << endl;
    16             return 0;
    17         }
    18     }
    19     cout <<"None"<<endl;
    20     return 0;
    21 }
  • 相关阅读:
    Kafka-1
    消息队列
    分布式分类
    认识分布式
    数据库引擎
    Django插入多条数据—bulk_create
    Django中update和save()同时作用
    联合唯一去重的SQL
    Direct3D11学习:(三)Direct3D11初始化
    Direct3D11学习:(零)常见问题及解决方法整理
  • 原文地址:https://www.cnblogs.com/zllwxm123/p/11154966.html
Copyright © 2011-2022 走看看