1154 Vertex Coloring (25 分)

1154 Vertex Coloring (25 分)

 

A proper vertex coloring is a labeling of the graph's vertices with colors such that no two vertices sharing the same edge have the same color. A coloring using at most k colors is called a (proper) k-coloring.

Now you are supposed to tell if a given coloring is a proper k-coloring.

Input Specification:

Each input file contains one test case. For each case, the first line gives two positive integers N and M (both no more than 1), being the total numbers of vertices and edges, respectively. Then M lines follow, each describes an edge by giving the indices (from 0 to N−1) of the two ends of the edge.

After the graph, a positive integer K (≤ 100) is given, which is the number of colorings you are supposed to check. Then K lines follow, each contains N colors which are represented by non-negative integers in the range of int. The i-th color is the color of the i-th vertex.

Output Specification:

For each coloring, print in a line k-coloring if it is a proper k-coloring for some positive k, or No if not.

Sample Input:

10 11
8 7
6 8
4 5
8 4
8 1
1 2
1 4
9 8
9 1
1 0
2 4
4
0 1 0 1 4 1 0 1 3 0
0 1 0 1 4 1 0 1 0 0
8 1 0 1 4 1 0 5 3 0
1 2 3 4 5 6 7 8 8 9

Sample Output:

4-coloring
No
6-coloring
No

着色，判断是否有两个连在一起的点用了同一颜色，没有就输出总颜色数量，否则输出No

#include <bits/stdc++.h>

using namespace std;
int n, m, k;
struct Node{
    int u,v;
}node[10005];
int val[10005], vis[10005];

bool dfs(){
    for(int i = 0; i < m; i++){
        if(val[node[i].u] == val[node[i].v])
            return false;
    }
    return true;
}

int main(){
    cin >> n >> m;
    int x,y;
    for(int i = 0 ; i < m; ++i){
        cin >> x >> y;
        node[i].u = x;
        node[i].v = y;
    }
    cin >> k;
    while(k--){
        map<int,int> mp;
        int cnt = 0;
        for(int i = 0; i < n; i++){
            cin >> val[i];
            if(mp[val[i]] == 0){
                mp[val[i]] = 1;
                cnt++;
            }
        }
        if(dfs()){
            cout <<cnt<<"-coloring"<<endl;
        }else{
            cout << "No" << endl;
        }
    }
    return 0;
}