Some natural number was written on the board. Its sum of digits was not less than k. But you were distracted a bit, and someone changed this number to n, replacing some digits with others. It's known that the length of the number didn't change.
You have to find the minimum number of digits in which these two numbers can differ.
The first line contains integer k (1 ≤ k ≤ 109).
The second line contains integer n (1 ≤ n < 10100000).
There are no leading zeros in n. It's guaranteed that this situation is possible.
Print the minimum number of digits in which the initial number and n can differ.
3
11
1
3
99
0
In the first example, the initial number could be 12.
In the second example the sum of the digits of n is not less than k. The initial number could be equal to n.
这题比赛的时候一直wa,原来是读错题意了(尴尬)。
其实读懂题意也是水题一道。
用了一个vector
1 #include <bits/stdc++.h> 2 #define ll long long int 3 #define M 100005 4 using namespace std; 5 char s[M]; 6 vector<int> v; 7 int main(){ 8 ll a; 9 scanf("%lld%s",&a,s); 10 int n=strlen(s); 11 ll cnt=0; 12 for(int i=0;i<n;i++){ 13 cnt+=(s[i]-'0'); 14 int f=s[i]-'0'; 15 v.push_back(9-f); 16 } 17 sort(v.begin(),v.end()); 18 int ans=0; 19 while(cnt<a&&v.size()){ 20 a-=v.back(); 21 v.pop_back(); 22 ans++; 23 } 24 cout<<ans<<endl; 25 return 0; 26 }