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  • PAT 甲级 1154 Vertex Coloring

    https://pintia.cn/problem-sets/994805342720868352/problems/1071785301894295552

    A proper vertex coloring is a labeling of the graph's vertices with colors such that no two vertices sharing the same edge have the same color. A coloring using at most k colors is called a (proper) k-coloring.

    Now you are supposed to tell if a given coloring is a proper k-coloring.

    Input Specification:

    Each input file contains one test case. For each case, the first line gives two positive integers N and M (both no more than 1), being the total numbers of vertices and edges, respectively. Then M lines follow, each describes an edge by giving the indices (from 0 to N1) of the two ends of the edge.

    After the graph, a positive integer K (≤ 100) is given, which is the number of colorings you are supposed to check. Then K lines follow, each contains N colors which are represented by non-negative integers in the range of int. The i-th color is the color of the i-th vertex.

    Output Specification:

    For each coloring, print in a line k-coloring if it is a proper k-coloring for some positive k, or No if not.

    Sample Input:

    10 11
    8 7
    6 8
    4 5
    8 4
    8 1
    1 2
    1 4
    9 8
    9 1
    1 0
    2 4
    4
    0 1 0 1 4 1 0 1 3 0
    0 1 0 1 4 1 0 1 0 0
    8 1 0 1 4 1 0 5 3 0
    1 2 3 4 5 6 7 8 8 9
    

    Sample Output:

    4-coloring
    No
    6-coloring
    No

    代码:

    #include <bits/stdc++.h>
    using namespace std;
    
    const int maxn = 1e4 + 10;
    int N ,M, K;
    vector<int> v[maxn];
    map<int, int> mp;
    
    int main() {
        scanf("%d%d", &N, &M);
        while(M --) {
            int a, b;
            scanf("%d%d", &a, &b);
            v[a].push_back(b);
            v[b].push_back(a);
        }
    
        scanf("%d", &K);
        while(K --) {
            mp.clear();
            set<int> s;
            s.clear();
            for(int i = 0; i < N; i ++) {
                int x;
                scanf("%d", &x);
                s.insert(x);
                mp[i] = x;
            }
    
            bool flag = true;
            for(int i = 0; i < N; i ++) {
                for(int j = 0; j < v[i].size(); j ++) {
                    if(mp[i] == mp[v[i][j]]) {
                        flag = false;
                        break;
                    }
                }
                if(flag) continue;
                else break;
            }
    
            if(!flag) printf("No
    ");
            else printf("%d-coloring
    ", (int)s.size());
        }
        return 0;
    }  

      今天第一题打卡 简单图论

    FHFHFH

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  • 原文地址:https://www.cnblogs.com/zlrrrr/p/10333027.html
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