zoukankan      html  css  js  c++  java
  • HDU 2164 Rock, Paper, or Scissors?

    http://acm.hdu.edu.cn/showproblem.php?pid=2164

    Problem Description
    Rock, Paper, Scissors is a two player game, where each player simultaneously chooses one of the three items after counting to three. The game typically lasts a pre-determined number of rounds. The player who wins the most rounds wins the game. Given the number of rounds the players will compete, it is your job to determine which player wins after those rounds have been played. 

    The rules for what item wins are as follows:

    ?Rock always beats Scissors (Rock crushes Scissors)
    ?Scissors always beat Paper (Scissors cut Paper)
    ?Paper always beats Rock (Paper covers Rock) 
     
    Input
    The first value in the input file will be an integer t (0 < t < 1000) representing the number of test cases in the input file. Following this, on a case by case basis, will be an integer n (0 < n < 100) specifying the number of rounds of Rock, Paper, Scissors played. Next will be n lines, each with either a capital R, P, or S, followed by a space, followed by a capital R, P, or S, followed by a newline. The first letter is Player 1抯 choice; the second letter is Player 2抯 choice.

     
    Output
    For each test case, report the name of the player (Player 1 or Player 2) that wins the game, followed by a newline. If the game ends up in a tie, print TIE.
     
    Sample Input
    3
    2
    R P
    S R
    3
    P P
    R S
    S R
    1
    P R
     
    Sample Output
    Player 2
    TIE
    Player 1
     
    代码:
    #include <bits/stdc++.h>
    using namespace std;
    
    char p1[1111], p2[1111];
    
    int cmp(char a, char b) {
    
        if(a == 'S') {
            if(b == 'P') return 2;
            if(b == 'R') return 1;
        }
    
        if(a == 'R') {
            if(b == 'S') return 2;
            if(b == 'P') return 1;
        }
    
        if(a == 'P') {
            if(b == 'R') return 2;
            if(b == 'S') return 1;
        }
    }
    
    int main() {
        int T;
        scanf("%d", &T);
        while(T --) {
            int x;
            scanf("%d", &x);
            int cnt = 0, ans = 0;
            getchar();
            for(int i = 1; i <= x; i ++) {
                scanf("%c %c", &p1[i], &p2[i]);
                getchar();
                if(cmp(p1[i], p2[i]) == 2)
                    cnt ++;
                else if(cmp(p1[i], p2[i]) == 1)
                    ans ++;
            }
    
            if(cnt > ans)
                printf("Player 1
    ");
            else if(cnt == ans)
                printf("TIE
    ");
            else
                printf("Player 2
    ");
        }
        return 0;
    }
    

      

     
  • 相关阅读:
    Zabbix监控mysql配置及故障告警配置
    Tesseract-OCR 字符识别---样本训练
    Wex5案例使用JSON传输Thinkphp后端对接,以达成数据正常输出
    Linux内核分析:recv、recvfrom、recvmsg函数实现
    libevent源码分析:evmap_io_active_函数
    libevent源码分析:epoll后端实现
    监听套接字不可写?
    Linux内核分析:dup、dup2的实现
    Linux内核分析:打开文件描述符实现
    libevent源码分析:http-server例子
  • 原文地址:https://www.cnblogs.com/zlrrrr/p/9417374.html
Copyright © 2011-2022 走看看