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  • PAT 甲级 1041 Be Unique

    https://pintia.cn/problem-sets/994805342720868352/problems/994805444361437184

    Being unique is so important to people on Mars that even their lottery is designed in a unique way. The rule of winning is simple: one bets on a number chosen from [1, 10^4^]. The first one who bets on a unique number wins. For example, if there are 7 people betting on 5 31 5 88 67 88 17, then the second one who bets on 31 wins.

    Input Specification:

    Each input file contains one test case. Each case contains a line which begins with a positive integer N (<=10^5^) and then followed by N bets. The numbers are separated by a space.

    Output Specification:

    For each test case, print the winning number in a line. If there is no winner, print "None" instead.

    Sample Input 1:

    7 5 31 5 88 67 88 17
    

    Sample Output 1:

    31
    

    Sample Input 2:

    5 888 666 666 888 888
    

    Sample Output 2:

    None

    代码:
    #include <bits/stdc++.h>
    using namespace std;
    
    const int maxn = 1e5 + 10;
    int a[maxn], num[maxn];
    
    int main() {
        int n;
        scanf("%d", &n);
        for(int i = 1; i <= n; i ++) {
            scanf("%d", &a[i]);
            num[a[i]] ++;
        }
    
        int cnt = 0;
        for(int i = 1; i <= n; i ++) {
            if(num[a[i]] == 1) {
                printf("%d
    ", a[i]);
                return 0;
            }
            if(num[a[i]] > 1)
                cnt ++;
        }
        if(cnt == n)
            printf("None
    ");
        return 0;
    }
    

      

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  • 原文地址:https://www.cnblogs.com/zlrrrr/p/9426365.html
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