java里如何实现两个等长度的字符串数组有多少个元素相同（从最左边开始，一旦遇到不同元素则跳出计数）

　　不多说，直接上干货！

package zhouls.bigdata.DataFeatureSelection.sim;

public class test {
    public static int stringArrayCompare (String[] a, String[] b) {  
        int num = 0;
        for (int i = 0; i < b.length; i++) {  
            if (b[i].equals(a[i])) {  
                num++;
            } else {//这里，控制从最左边开始，一旦遇到不同元素，则跳出  
                break;
            }  
        }  
    return num;  
    }


    public static void main(String[] args) {  
        String[] a = { "1","1","1","0" };
        String[] b = { "1","1","1","1" };

                
        System.out.println(stringArrayCompare(a, b));  
    }  
}  

　　如果

 String[] a = { "1","1","1","0" };
 String[] b = { "1","1","0","0" };

　　则，结果也是2