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  • POJ 2418 Hardwood Species

      字典树 或者  map......

      map  8000+ ms

      

     1 #include <iostream>
     2 #include <algorithm>
     3 #include <cstdio>
     4 #include <cstring>
     5 #include <cmath>
     6 #include <cstdlib>
     7 #include <queue>
     8 #include <map>
     9 #include <string>
    10 #include <utility>
    11 #include <vector>
    12 #include <iomanip>
    13 
    14 using namespace std;
    15 
    16 struct cmp
    17 {
    18     bool operator() (pair<string,int> a, pair<string,int> b)
    19     {
    20         return a > b;
    21     }
    22 };
    23 
    24 priority_queue<int,vector< pair<string,int> >,cmp> q;
    25 
    26 map<string,int> tree;
    27 
    28 int main()
    29 {
    30 
    31 
    32     pair<string,int> stu;
    33 
    34     string name;
    35 
    36     int count = 0;
    37 
    38     while(getline(cin,name) != NULL)
    39     {
    40         ++tree[name];
    41         ++count;
    42     }
    43 
    44     map<string,int>::iterator it = tree.begin();
    45 
    46     while(it != tree.end())
    47     {
    48         cout<<it->first<<' '<<setiosflags(ios::fixed)<<setprecision(4)<<(it->second*100.0/count)<<endl;
    49         ++it;
    50     }
    51 
    52     return 0;
    53 }
    View Code

      

      字典树 1100+ ms 

      

     1 #include<stdio.h>
     2 #include<stdlib.h>
     3 #include<string.h>
     4 
     5 int max;
     6 
     7 struct T
     8 {
     9     char name[40];
    10     int sum,mark;
    11     struct T *r,*l;
    12 };
    13 
    14 void init(struct T *root)
    15 {
    16     root->r = NULL;
    17     root->l = NULL;
    18     root->sum = 0;
    19     root->mark = 1;
    20 }
    21 
    22 void link(struct T *p,char *temp)
    23 {
    24         if(p->mark)
    25         {
    26             strcpy(p->name,temp);
    27             p->sum++;
    28             p->mark = 0;
    29         }
    30         else
    31         {
    32             int    mark = strcmp(temp,p->name);
    33             if(!mark) p->sum++;
    34             else if(mark > 0)
    35             {
    36                 if(p->l != NULL)
    37                 {
    38                     link(p->l,temp);
    39                     return;
    40                 }
    41                 else
    42                 {
    43                     struct T *t;
    44                     t = (struct T *)malloc(sizeof(struct T));
    45                     init(t);
    46                     p->l = t;
    47                     link(p->l,temp);
    48                     return;
    49                 }
    50             }
    51             else if(mark < 0)
    52             {
    53                 if(p->r != NULL)
    54                 {
    55                     link(p->r,temp);
    56                     return;
    57                 }
    58                 else
    59                 {
    60                     struct T *t;
    61                     t = (struct T *)malloc(sizeof(struct T));
    62                     init(t);
    63                     p->r = t;
    64                     link(p->r,temp);
    65                     return;
    66                 }
    67             }
    68         }
    69 }
    70 
    71 void output(struct T *root)
    72 {
    73     if(root->r != NULL)
    74     {
    75         output(root->r);
    76         printf("%s %.4lf
    ",root->name,100.0*root->sum/max);
    77     }
    78     else printf("%s %.4lf
    ",root->name,100.0*root->sum/max);
    79     if(root->l != NULL)
    80     {
    81         output(root->l);
    82     }
    83 }
    84 
    85 int main()
    86 {
    87     struct T *root;
    88     root = (struct T *)malloc(sizeof(struct T));
    89     init(root);
    90     char temp[40];
    91     max = 0;
    92     while(gets(temp) != NULL)
    93     {
    94         max++;
    95         link(root,temp);
    96     }
    97     output(root);
    98     return 0 ;
    99 }
    View Code
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  • 原文地址:https://www.cnblogs.com/zmx354/p/3268906.html
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