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  • 336. Palindrome Pairs

        /*
         * 336. Palindrome Pairs
         * 2016-7-10 by Mingyang
         */
        class TrieNode {
            TrieNode[] next;
            int index;
            List<Integer> list;        
            TrieNode() {
                next = new TrieNode[26];
                index = -1;
                list = new ArrayList<>();
            }
        }
        public List<List<Integer>> palindromePairs(String[] words) {
            List<List<Integer>> res = new ArrayList<>();    
            TrieNode root = new TrieNode();        
            for (int i = 0; i < words.length; i++) {
                addWord(root, words[i], i);
            }        
            for (int i = 0; i < words.length; i++) {
                search(words, i, root, res);
            }        
            return res;
        }
        private void addWord(TrieNode root, String word, int index) {
            for (int i = word.length() - 1; i >= 0; i--) {
                if (root.next[word.charAt(i) - 'a'] == null) {
                    root.next[word.charAt(i) - 'a'] = new TrieNode();
                }        
                if (isPalindrome(word, 0, i)) {
                    root.list.add(index);
                }            
                root = root.next[word.charAt(i) - 'a'];
            }        
            root.list.add(index);
            root.index = index;
        }
        private void search(String[] words, int i, TrieNode root, List<List<Integer>> list) {
            for (int j = 0; j < words[i].length(); j++) {    
                if (root.index >= 0 && root.index != i && isPalindrome(words[i], j, words[i].length() - 1)) {
                    list.add(Arrays.asList(i, root.index));
                }            
                root = root.next[words[i].charAt(j) - 'a'];
                  if (root == null) return;
            }        
            for (int j : root.list) {
                if (i == j) continue;
                list.add(Arrays.asList(i, j));
            }
        }
        private boolean isPalindrome(String word, int i, int j) {
            while (i < j) {
                if (word.charAt(i++) != word.charAt(j--)) return false;
            }        
            return true;
        }
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  • 原文地址:https://www.cnblogs.com/zmyvszk/p/5659058.html
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