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  • python--格式化输出,for循环,range

    格式化输出

    %s: 字符串的占位符, 可以放置任何内容(数字)

    %d: 数字的占位符

    name = "zouzou"
    print("%s活了人生的%%2" % name)  # 如果字符串中有了占位符. 那么后面的所有的%都是占位. 需要转义,用%转义
    print("邹邹活了人生的%5")  # 这句话中没有占位符. %还是%

    结果:

    zouzou活了人生的%2
    邹邹活了人生的%5
    name = input('name:')
    age = input('age:')
    job = input('job:')
    salary = input('salary:')
    info = '''
    ----------------info fo %s------------
    name:%s
    age:%s
    job:%s
    salary:%s
    ''' % (name, name, age, job, salary)
    print(info)

    结果:

    name = input('name:')
    age = input('age:')
    job = input('job:')
    salary = input('salary:')
    info = '''
    ----------------info fo {_name}------------
    name:{_name}
    age:{_age}
    job:{_job}
    salary:{_salary}
    '''.format(_name=name,
               _age=age,
               _job=job,
               _salary=salary)
    print(info)

    结果:

    name = input('name:')
    age = input('age:')
    job = input('job:')
    salary = input('salary:')
    info = '''
    ----------------info fo {0}------------
    name:{0}
    age:{1}
    job:{2}
    salary:{3}
    '''.format(name, age, job, salary)
    print(info)

    结果:

     for循环,range

    range有一个参数:结束为止

    两个参数: 1. 起始位置, 2.结束位置

    三个参数: 1. 起始位置, 2. 结束位置. 3.步长

    age_of_oldboy = 56
    for i in range(3):
        guess_age = int(input('guess age:'))
        if guess_age == age_of_oldboy:
            print("yes, you got it. ")
            break
        elif guess_age > age_of_oldboy:
            print("think smaller...")
        else:
            print("thing bigger...")
    else:
        print("you have tried too many times...")

    当for循环执行三次结束后执行else下的print。如果中途遇到break,就结束,不执行else下的print

    for i in range(10):
        print(i)
    # 打印出了0,1,2,3,4,5,6,7,8,9
    for i in range(0, 10, 3):
        print(i)
    # 打印出了0,3,6,9,也就是步长为3,默认为1.
    age_of_oldboy = 56
    count = 0
    while count < 3:
        guess_age = int(input('guess age:'))
        if guess_age == age_of_oldboy:
            print("yes, you got it. ")
            break
        elif guess_age > age_of_oldboy:
            print("think smaller...")
        else:
            print("thing bigger...")
        count = count + 1
        if count == 3:
            countine_confirm = input('是否需要继续下去,n键退出,其余键继续')
            if countine_confirm != 'n':
                count = 0

    当输入错三次是,会提示是否需要继续,如果是n就结束,其余键将count重新赋值0,每三次问一次,输对时直接结束

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  • 原文地址:https://www.cnblogs.com/zouzou-busy/p/12989835.html
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