jQuery, js 验证两次输了密码的一相同

<div class="form-group">
                <label class="col-sm-2 control-label font">新密码</label>
                    <div class="col-xs-10">
                        <input type="password" class="form-control bt" name="pwd" id="pwd" placeholder="请设置新密码">
                    </div>
            </div><br/><br/><br/>
             
            <div class="form-group">
                <label class="col-sm-2 control-label font">确认新密码</label>
                    <div class="col-xs-10">
                        <input type="password" class="form-control bt" name="pwd" id="pwd1" placeholder="请再次填写新密码" onkeyup="validate()"><span id="tishi"></span>
                    </div>
            </div><br/><br/>
             
            <button type="button" class="btn btn-primary btn-lg btn-block xg" id="xiugai" >修改</button>

JS写法
 1 function validate() {
    var pwd1 = document.getElementById("pwd").value;
    var pwd2 = document.getElementById("pwd1").value;
 
<!-- 对比两次输入的密码 -->
    if(pwd1 == pwd2)
     {
        document.getElementById("tishi").innerHTML="<font color='green'>两次密码相同</font>";
        document.getElementById("button").disabled = false;
     }
else {
        document.getElementById("tishi").innerHTML="<font color='red'>两次密码不相同</font>";
        document.getElementById("button").disabled = true;
      }
}


JQuery写法

function validate() {
     
    var pwd = $("#pwd").val();
    var pwd1 = $("#pwd1").val();
<!-- 对比两次输入的密码 -->
    if(pwd == pwd1)
     {
        $("#tishi").html("两次密码相同");
         $("#tishi").css("color","green");
    $("#xiugai").removeAttr("disabled");
     }
else {
        $("#tishi").html("两次密码不相同");
         $("#tishi").css("color","red")
          $("button").attr("disabled","disabled");   
      }
}