Problem Description
we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).
Give you a letter x and a number y , you should output the result of y+f(x).
Input
On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.
Output
for each case, you should the result of y+f(x) on a line.
Sample Input
6
R 1
P 2
G 3
r 1
p 2
g 3
Sample Output
19
18
10
-17
-14
-4
1 #include <stdio.h> 2 #include <ctype.h> 3 4 int main(){ 5 int T; 6 char c; 7 int number; 8 int result; 9 10 scanf("%d",&T); 11 12 while(T--){ 13 getchar(); 14 scanf("%c%d",&c,&number); 15 16 if(islower(c)!=0){ 17 result=c-'a'+1; 18 result=-result; 19 result+=number; 20 } 21 22 else{ 23 result=c-'A'+1; 24 result+=number; 25 } 26 27 printf("%d ",result); 28 } 29 30 return 0; 31 }