Problem Description
Calculate S(n).
S(n)=13+23 +33 +......+n3 .
S(n)=13+23 +33 +......+n3 .
Input
Each line will contain one integer N(1 < n < 1000000000). Process to end of file.
Output
For each case, output the last four dights of S(N) in one line.
Sample Input
1
2
Sample Output
0001
0009
1 #include <stdio.h> // 运用数学公式:1^3 +2^3 +3^3 +……+n^3 =[n(n+1)/2]^2 2 3 int main(){ 4 int n; 5 int result; 6 7 while(scanf("%d",&n)!=EOF){ 8 n=n%10000; 9 result=(n*(n+1)/2)%10000; 10 result=(result*result)%10000; 11 12 printf("%04d ",result); 13 } 14 15 return 0; 16 }