zoukankan      html  css  js  c++  java
  • So easy

    Problem Description
    Small W gets two files. There are n integers in each file. Small W wants to know whether these two files are same. So he invites you to write a program to check whether these two files are same. Small W thinks that two files are same when they have the same integer set.
    For example file A contains (5,3,7,7),and file B contains (7,5,3,3). They have the same integer set (3,5,7), so they are same.
    Another sample file C contains(2,5,2,5), and file D contains (2,5,2,3).
    The integer set of C is (2,5),but the integer set of D is (2,3,5),so they are not same.
    Now you are expected to write a program to compare two files with size of n.
     
    Input
    Multi test cases (about 100). Each case contain three lines. The first line contains one integer n represents the size of file. The second line contains n integers a1,a2,a3,,an - represents the content of the first file. The third line contains n integers b1,b2,b3,,bn - represents the content of the second file.
    Process to the end of file.
    1n100
    1ai,bi1000000000
     
    Output
    For each case, output "YES" (without quote) if these two files are same, otherwise output "NO" (without quote).
     
    Sample Input
    3
    1 1 2
    1 2 2
    4
    5 3 7 7
    7 5 3 3
    4
    2 5 2 3
    2 5 2 5
    3
    1 2 3
    1 2 4
     
    Sample Output
    YES
    YES
    NO
    NO
     
      1 #include <stdio.h> 
      2 
      3 int main(){
      4     int n;
      5     int number;
      6     int i;
      7     int j;
      8     int array1[101];
      9     int array2[101];
     10     int length1;
     11     int length2;
     12     int temp;
     13 
     14     while(scanf("%d",&n)!=EOF){
     15         length1=0;
     16         for(i=0;i<n;i++){
     17             scanf("%d",&number);
     18 
     19             if(i==0){
     20                 array1[0]=number;
     21                 length1++;
     22                 continue;
     23             }
     24 
     25             for(j=0;j<length1;j++){
     26                 if(number==array1[j])
     27                     break;
     28             }
     29 
     30             if(j==length1){
     31                 array1[length1]=number;
     32                 length1++;
     33             }
     34         }
     35 
     36         for(i=0;i<length1-1;i++){
     37             for(j=i+1;j<length1;j++){
     38                 if(array1[i]>array1[j]){
     39                     temp=array1[i];
     40                     array1[i]=array1[j];
     41                     array1[j]=temp;
     42                 }
     43             }
     44         }
     45 
     46         /*for(i=0;i<length1;i++)
     47             printf("%d ",array1[i]);
     48         printf("
    ");*/
     49 
     50         length2=0;
     51         for(i=0;i<n;i++){
     52             scanf("%d",&number);
     53 
     54             if(i==0){
     55                 array2[0]=number;
     56                 length2++;
     57                 continue;
     58             }
     59 
     60             for(j=0;j<length2;j++){
     61                 if(number==array2[j])
     62                     break;
     63             }
     64 
     65             if(j==length2){
     66                 array2[length2]=number;
     67                 length2++;
     68             }
     69         }
     70 
     71         for(i=0;i<length2-1;i++){
     72             for(j=i+1;j<length2;j++){
     73                 if(array2[i]>array2[j]){
     74                     temp=array2[i];
     75                     array2[i]=array2[j];
     76                     array2[j]=temp;
     77                 }
     78             }
     79         }
     80 
     81         /*for(i=0;i<length2;i++)
     82             printf("%d ",array2[i]);
     83         printf("
    ");*/
     84 
     85         if(length1!=length2){
     86             printf("NO
    ");
     87             continue;
     88         }
     89 
     90         for(i=0;i<length1;i++){
     91             if(array1[i]!=array2[i]){
     92                 printf("NO
    ");
     93                 break;
     94             }
     95         }
     96 
     97         if(i==length1)
     98             printf("YES
    ");
     99 
    100     }
    101         
    102     return 0;
    103 }
  • 相关阅读:
    OSI安全体系结构
    PHP 二维数组根据相同的值进行合并
    Java实现 LeetCode 17 电话号码的字母组合
    Java实现 LeetCode 16 最接近的三数之和
    Java实现 LeetCode 16 最接近的三数之和
    Java实现 LeetCode 16 最接近的三数之和
    Java实现 LeetCode 15 三数之和
    Java实现 LeetCode 15 三数之和
    Java实现 LeetCode 15 三数之和
    Java实现 LeetCode 14 最长公共前缀
  • 原文地址:https://www.cnblogs.com/zqxLonely/p/4079949.html
Copyright © 2011-2022 走看看