/*
求sum{C(n/i,k)}
*/
#include<bits/stdc++.h>
using namespace std;
#define N 500005
#define mod 998244353
#define ll long long
ll n,k,ans;
int F[N], Finv[N], inv[N];///F是阶层 Finv是逆元的阶层
void init(){
inv[1] = 1;
for(int i = 2; i < N; i++)
inv[i] = (mod - mod/i) * 1ll * inv[mod % i] % mod;
F[0] = Finv[0] = 1;
for(int i = 1; i < N; i++){
F[i] = F[i-1] * 1ll * i % mod;
Finv[i] = Finv[i-1] * 1ll * inv[i] % mod;
}
}
int comb(int n, int m){ /// C(n,m)
if(m < 0 || m > n) return 0;
return F[n] * 1ll * Finv[n-m] % mod * Finv[m] % mod;
}
int main(){
init();
cin>>n>>k;
for(int i=1;i<=n;i++)
ans=(ans+comb(n/i-1,k-1))%mod;
cout<<ans<<'
';
}