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  • A的B次方

    Problem Description

    lcy gives a hard puzzle to feng5166,lwg,JGShining and Ignatius: gave a and b,how to know the a^b.everybody objects to this BT problem,so lcy makes the problem easier than begin.
    this puzzle describes that: gave a and b,how to know the a^b's the last digit number.But everybody is too lazy to slove this problem,so they remit to you who is wise.

    Input

    There are mutiple test cases. Each test cases consists of two numbers a and b(0<a,b<=2^30)

    Output

    For each test case, you should output the a^b's last digit number.

    Sample Input

    7 66 8 800

    Sample Output

    9 6

     

    #include <stdio.h>
    int main()
    {
        int a,b;
        int num[8][4]={{6,2,4,8},{1,3,9,7},{6,4,6,4},{5,5,5,5},{6,6,6,6},{1,7,9,3},{6,8,4,2},{1,9,1,9}};
        while( scanf("%d%d",&a,&b)!=EOF )
        {
             int temp = a;
             if( temp==1 )
             {
                        printf("1\n");
             }
             else if(temp == 0)
             {
                        printf("0\n");
              }
              else
              {
                     if( temp == 5 )
                         printf( "5\n" );
                      else
                         printf("%d\n",num[temp-2][b%4]);         

              }
        }
        return 0;
    }

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  • 原文地址:https://www.cnblogs.com/zsj576637357/p/2250531.html
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