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    克鲁斯卡尔

    #include <cstdio>
    #include <algorithm>
    using namespace std;
    #define maxn 200005
    #define ll long long
    int fa[maxn], n, m;
    struct Edge
    {
        int x;
        int y;
        int z;
    } edge[maxn];
    bool cmp(Edge a,Edge b)
    {
        return a.z < b.z;
    }
    int Find(int x)
    {
        if(x==fa[x])
            return x;
        else
            return fa[x] = Find(fa[x]);
    }
    int main()
    {
        scanf("%d%d", &n, &m);
        int ans = 0;
        for (int i = 1; i <= m;i++)
        {
            scanf("%d%d%d", &edge[i].x, &edge[i].y, &edge[i].z);
        }
        sort(edge + 1, edge + 1 + m,cmp);
        for (int i = 1; i <= n;i++)
            fa[i] = i;
        for (int i = 1; i <= m;i++)
        {
            int x = Find(edge[i].x);
            int y = Find(edge[i].y);
            if(x==y)
                continue;
            fa[x] = y;
            ans += edge[i].z;
        }
        printf("%d
    ",ans);
        system("pause");
    }
    

      

    普里姆

    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    using namespace std;
    #define maxn1 100005
    #define maxn2 3005
    #define ll long long
    int a[maxn2][maxn2], d[maxn1], n, m, ans;
    bool vis[maxn2][maxn2];
    void Prim()
    {
    	memset(d, 0x3f, sizeof(d));
    	memset(vis, 0, sizeof(vis));
    	d[1] = 0;
    	for (int i = 1; i < n;i++)
    	{
    		int x = 0;
    		for (int j = 1; j <= n;j++)
    			if(!vis[j]&&(x==0||d[j]<d[x]))
    				x = j;
    		vis[x] = 1;
    		for (int y = 1; y <= n;y++)
    			if(!vis[y])
    				d[y] = min(d[y], a[x][y]);
    	}
    }
    int main()
    {
    	scanf("%d%d", &n, &m);
    	memset(a,0x3f,sizeof(a));
    	for (int i = 1; i <= n;i++)
    		a[i][i] = 0;
    	for (int i = 1; i <= m;i++)
    	{
    		int x, y, z;
    		scanf("%d%d%d", &x, &y, &z);
    		a[x][y] = a[y][x] = min(z, a[x][y]);   //有些题两点之间会有重边
    	}
    	Prim();
    	for (int i = 2; i <= n;i++)
    		ans += d[i];
    	printf("%d
    ", ans);
    }
    

      

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  • 原文地址:https://www.cnblogs.com/zssst/p/11337816.html
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