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  • Atcoder regular Contest 073(C

    Atcoder regular Contest 073(C - Sentou)

    传送门

    每个人对开关的影响区间为a[i]--a[i]+t,因此此题即为将所有区间离散化后求所有独立区间的长度和

    #include<queue>
    #include<cmath>
    #include<cstdio>
    #include<cstring>
    #include<cstdlib>
    #include<iostream>
    #include<algorithm>
    #define ll long long
    #define inf 1000000000LL
    #define mod 1000000007
    using namespace std;
    int read()
    {
        int x=0,f=1;
        char ch=getchar();
        while(ch<'0'||ch>'9')
        {
            if(ch=='-')f=-1;
            ch=getchar();
        }
        while(ch>='0'&&ch<='9')
        {
            x=x*10+ch-'0';
            ch=getchar();
        }
        return x*f;
    }
    const int N=2e5+10;
    pair<ll,ll> B[N*2];
    int main()
    {
       // while(true)
        {
            int n=read(),t=read();
            int top=0;
            ll x;
            for(int i=0;i<n;i++)
            {
                x=read();
                B[top].first=x;
                B[top].second=-1;
                top++;
               // cout<<x+t<<endl;
                B[top].first=x+t;
                B[top].second=1;
                top++;
            }
            sort(B,B+top);
            int count=0;
            ll pre=0,ans=0;
            bool first=1;
            for(int i=0;i<top;i++)
            {
                if(B[i].second==1){
                    count++;
                    if(count==0){
                        ans+=B[i].first-pre;
                    }
                }
                if(B[i].second==-1){
                    count--;
                    if(count==-1){
                        pre=B[i].first;
                    }
                }
            }
            printf("%I64d
    ",ans);
        }
        return 0;
    }
    
    
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  • 原文地址:https://www.cnblogs.com/zsyacm666666/p/6786613.html
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