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  • struts2捕获action类异常

    首先是STRUTS.XML的配置。重点在于配置文件:
    <!-- struts2捕获action类异常 -->
            <global-results>
    <result name="error">/error.jsp</result>
    </global-results>
    <global-exception-mappings>
    <exception-mapping result="error" exception="java.lang.Exception"></exception-mapping>
    </global-exception-mappings>
    这样一块。


    <?xml version="1.0" encoding="UTF-8" ?

    > <!DOCTYPE struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.3//EN" "http://struts.apache.org/dtds/struts-2.3.dtd"> <struts> <!-- 採用注解的方式 --> <constant name="struts.enable.DynamicMethodInvocation" value="true" /> <constant name="struts.devMode" value="true" /> <package name="default" namespace="" extends="struts-default"> <!-- struts2捕获action类异常 --> <global-results> <result name="error">/error.jsp</result> </global-results> <global-exception-mappings> <exception-mapping result="error" exception="java.lang.Exception"></exception-mapping> </global-exception-mappings> <action name="link" class="com.test.action.LoginAction"> <result>/result.jsp</result> </action> <action name="linkIOC" class="com.test.action.LoginActionIOC"> <result>/result.jsp</result> </action> </package> <!-- Add packages here --> </struts>

    測试类

    package com.test.action;
    
    import java.util.Map;
    
    import com.opensymphony.xwork2.ActionContext;
    import com.opensymphony.xwork2.ActionSupport;
    
    public class LoginAction extends ActionSupport{
    
    	/**
    	 * 
    	 */
    	private static final long serialVersionUID = 1L;
    	
    	private Map request;
    	private Map session;
    	private Map application;
    	
    	public LoginAction()
    	{
    		System.out.println("loginaction构造函数!");
    		request=(Map) ActionContext.getContext().get("request");
    		session=ActionContext.getContext().getSession();
    		application=ActionContext.getContext().getApplication();
    	}
    	
    	public String execute()
    	{
    		//System.out.println(request);
    		//System.out.println(session);
    		//System.out.println(application);
    		
    		int i=100/0;/*这个地方会抛出异常,默认情况下struts2是不会捕获异常,直接抛出*/
    		
    		request.put("msg", "欢迎你!");
    		return SUCCESS;
    	}
    
    }
    

    输出结果



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  • 原文地址:https://www.cnblogs.com/zsychanpin/p/6732657.html
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