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  • HDU 1043 Eight (BFS·八数码·康托展开)

    题意  输出八数码问题从给定状态到12345678x的路径

    用康托展开将排列相应为整数  即这个排列在全部排列中的字典序  然后就是基础的BFS了

    #include <bits/stdc++.h>
    using namespace std;
    const int N = 5e5, M = 9;
    int x[4] = { -1, 1, 0, 0};
    int y[4] = {0, 0, -1, 1};
    int fac[] = {1, 1, 2, 6, 24, 120, 720, 5040, 40320};
    int puz[N][M], nex[N], dir[N], vis[N], q[N];
    
    int getCantor(int a[])  //康托展开  将排列转化为整数
    {
        int ret = 0;
        for(int i = 0; i < M; ++i)
        {
            for(int j = i + 1; j < M; ++j)
                if(a[j] < a[i]) ret += fac[M - i - 1];
        }
        return ret;
    }
    
    void bfs()
    {
        int t[M] = {1, 2, 3, 4, 5, 6, 7, 8, 0};
        int id = getCantor(t);
        dir[id] = -1;
    
        memcpy(puz[id], t, sizeof(t));
        memset(vis, 0, sizeof(vis));
    
        int r, c, k, nr, nc, nk, nid;
        int front = 0, rear = 0;
        q[rear++] = id;
        vis[id] = 1;
    
        while(front < rear)
        {
            int id = q[front++];
            memcpy(t, puz[id], sizeof(t));
            for(k = 0; t[k]; ++k);  //找0的位置
            r = k / 3, c = k % 3;  //一维转二维
    
            for(int i = 0; i < 4; ++i)
            {
                nr = r + x[i], nc = c + y[i], nk = nr * 3 + nc;
    
                if(nr < 0 || nr > 2 || nc < 0 || nc > 2) continue;
                swap(t[k], t[nk]);
                nid = getCantor(t);
                memcpy(puz[nid], t, sizeof(t));
                swap(t[k], t[nk]);
    
                if(vis[nid]) continue;
                vis[nid] = 1;
                q[rear++] = nid;
                nex[nid] = id;
                dir[nid] = i;
            }
        }
    }
    
    int main()
    {
        char t[5], sdir[] = "durl";
        int s[M], id;
        bfs();
    
        while(~scanf("%s", t))
        {
            s[0] = t[0] == 'x' ? 0 : t[0] - '0';
            for(int i = 1; i < M; ++i)
            {
                scanf("%s", t);
                s[i] = t[0] == 'x' ? 0 : t[0] - '0';
            }
    
            id = getCantor(s);
            if(!vis[id]) puts("unsolvable");
            else
            {
                while(dir[id] >= 0)
                {
                    printf("%c", sdir[dir[id]]);
                    id = nex[id];
                }
                puts("");
            }
        }
        return 0;
    }
    //Last modified :   2015-07-05 11:15

    
    

    Eight


    Problem Description
    The 15-puzzle has been around for over 100 years; even if you don't know it by that name, you've seen it. It is constructed with 15 sliding tiles, each with a number from 1 to 15 on it, and all packed into a 4 by 4 frame with one tile missing. Let's call the missing tile 'x'; the object of the puzzle is to arrange the tiles so that they are ordered as: 
     1  2  3  4
     5  6  7  8
     9 10 11 12
    13 14 15  x
    

    where the only legal operation is to exchange 'x' with one of the tiles with which it shares an edge. As an example, the following sequence of moves solves a slightly scrambled puzzle: 
     1  2  3  4     1  2  3  4     1  2  3  4     1  2  3  4
     5  6  7  8     5  6  7  8     5  6  7  8     5  6  7  8
     9  x 10 12     9 10  x 12     9 10 11 12     9 10 11 12
    13 14 11 15    13 14 11 15    13 14  x 15    13 14 15  x
                r->            d->            r->
    

    The letters in the previous row indicate which neighbor of the 'x' tile is swapped with the 'x' tile at each step; legal values are 'r','l','u' and 'd', for right, left, up, and down, respectively. 

    Not all puzzles can be solved; in 1870, a man named Sam Loyd was famous for distributing an unsolvable version of the puzzle, and 
    frustrating many people. In fact, all you have to do to make a regular puzzle into an unsolvable one is to swap two tiles (not counting the missing 'x' tile, of course). 

    In this problem, you will write a program for solving the less well-known 8-puzzle, composed of tiles on a three by three 
    arrangement.
     

    Input
    You will receive, several descriptions of configuration of the 8 puzzle. One description is just a list of the tiles in their initial positions, with the rows listed from top to bottom, and the tiles listed from left to right within a row, where the tiles are represented by numbers 1 to 8, plus 'x'. For example, this puzzle 

    1 2 3 
    x 4 6 
    7 5 8 

    is described by this list: 

    1 2 3 x 4 6 7 5 8
     

    Output
    You will print to standard output either the word ``unsolvable'', if the puzzle has no solution, or a string consisting entirely of the letters 'r', 'l', 'u' and 'd' that describes a series of moves that produce a solution. The string should include no spaces and start at the beginning of the line. Do not print a blank line between cases.
     

    Sample Input
    2 3 4 1 5 x 7 6 8
     

    Sample Output
    ullddrurdllurdruldr
     


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  • 原文地址:https://www.cnblogs.com/zsychanpin/p/6747937.html
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