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  • [题解] [HEOI2013] Segment

    题面

    题解

    李超线段树

    为了与机房大佬 HYJ 同步伐

    学习笔记请移步 yyb的博客

    Code

    #include <algorithm>
    #include <iostream>
    #include <cstring>
    #include <cstdio>
    #include <cmath>
    const int N = 100005;
    const int mod = 39989;
    #define val(id, x) (k[id] * x + b[id])
    using namespace std;
    
    int Q, cnt, ans; 
    struct node
    {
    	int id;
    	double k, b; 
    } t[N << 2];
    double k[N], b[N]; 
    
    template < typename T >
    inline T read()
    {
    	T x = 0, w = 1; char c = getchar();
    	while(c < '0' || c > '9') { if(c == '-') w = -1; c = getchar(); }
    	while(c >= '0' && c <= '9') x = x * 10 + c - '0', c = getchar();
    	return x * w; 
    }
    
    void pushtag(int p, int l, int r, int id)
    {
    	if(!t[p].id) { t[p] = (node) { id, k[id], b[id] }; return; }
    	int now = t[p].id; 
    	double l1 = val(now, l), r1 = val(now, r), l2 = val(id, l), r2 = val(id, r);
    	if(l2 <= l1 && r2 <= r1) return;
    	if(l1 < l2 && r1 < r2) { t[p] = (node) { id, k[id], b[id] }; return; }
    	int mid = (l + r) >> 1; double x = (b[id] - b[now]) / (k[now] - k[id]);
    	if(x <= mid)
    	{
    		if(l1 <= l2) pushtag(p << 1, l, mid, id);
    		else pushtag(p << 1, l, mid, now), t[p] = (node) { id, k[id], b[id] }; 
    	}
    	else
    	{
    		if(l1 <= l2) pushtag(p << 1 | 1, mid + 1, r, now), t[p] = (node) { id, k[id], b[id] };
    		else pushtag(p << 1 | 1, mid + 1, r, id); 
    	}
    }
    
    void modify(int p, int l, int r, int ql, int qr, int id)
    {
    	if(ql <= l && r <= qr) { pushtag(p, l, r, id); return; }
    	int mid = (l + r) >> 1;
    	if(ql <= mid) modify(p << 1, l, mid, ql, qr, id);
    	if(mid < qr) modify(p << 1 | 1, mid + 1, r, ql, qr, id); 
    }
    
    void check(int &a, int c, int x)
    {
    	double y0 = val(a, x), y1 = val(c, x);
    	if(y1 > y0 || (fabs(y1 - y0) < 1e-7 && a > c)) a = c; 
    }
    
    int query(int p, int l, int r, int x)
    {
    	if(l == r) return t[p].id;
    	int mid = (l + r) >> 1, res = t[p].id; 
    	if(x <= mid) check(res, query(p << 1, l, mid, x), x);
    	else check(res, query(p << 1 | 1, mid + 1, r, x), x);
    	return res; 
    }
    
    int main()
    {
    /*	freopen("cpp.in", "r", stdin); 
    	freopen("cpp.out", "w", stdout); 
    */	Q = read <int> ();
    	int opt, x0, x1, y0, y1; 
    	while(Q--)
    	{
    		opt = read <int> ();
    		if(!opt)
    		{
    //			printf("%d
    ", x0); 
    			x0 = read <int> (), x0 = ((x0 + ans - 1) % mod + 1); 
    			printf("%d
    ", ans = query(1, 1, mod, x0)); 
    		}
    		else
    		{
    			x0 = read <int> (), y0 = read <int> (), x1 = read <int> (), y1 = read <int> ();
    			x0 = ((x0 + ans - 1) % mod + 1), y0 = ((y0 + ans - 1) % 1000000000 + 1);
    			x1 = ((x1 + ans - 1) % mod + 1), y1 = ((y1 + ans - 1) % 1000000000 + 1);
    			if(x0 > x1) swap(x0, x1), swap(y0, y1);
    //			printf("%d %d
    ", x0, x1); 
    			k[++cnt] = 1.0 * (y1 - y0) / (x1 - x0), b[cnt] = 1.0 * y0 - k[cnt] * x0;
    			modify(1, 1, mod, x0, x1, cnt); 
    		}
    	}
    	return 0; 
    }
    /*
      3
      1 3 5 7 7
      1 3 9 7 3
      0 5
     */
    
    
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  • 原文地址:https://www.cnblogs.com/ztlztl/p/12031635.html
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