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  • CodeForces 631C Print Check

    排序+构造+预处理

    #include<cstdio>
    #include<cstring>
    #include<cmath>
    #include<algorithm>
    using namespace std;
    
    const int maxn = 200000 + 10;
    int n, m;
    int a[maxn], ans[maxn];
    int op[maxn], e[maxn];
    int pos[maxn];
    int first, last;
    int flag;
    int p;
    int tot;
    
    bool cmp(const int &a, const int &b)
    {
        return a>b;
    }
    
    int main()
    {
        while (~scanf("%d%d", &n, &m))
        {
            for (int i = 1; i <= n; i++) scanf("%d", &a[i]);
            for (int i = 1; i <= m; i++) scanf("%d%d", &op[i], &e[i]);
            memset(ans, 0, sizeof ans);
            tot = 0; memset(pos, -1, sizeof pos);
            pos[m] = m;
            for (int i = m - 1; i >= 1; i--)
            {
                pos[i] = pos[i + 1];
                if (e[i] > e[pos[i + 1]]) pos[i] = i;
            }
    
            p = pos[1];
            if (op[p] == 1){sort(a + 1, a + 1 + e[p]); flag = 1;}
            else{sort(a + 1, a + 1 + e[p], cmp);flag = 2;}
            first = 1; last = e[p];
            for (int i = e[p] + 1; i <= n; i++) ans[i] = a[i], tot = tot + 1;
            while (tot<n)
            {
                p = pos[p + 1]; if (p == -1) break;
                if (first>last)
                {
                    for (int i = last; i <= first - e[p]; i++) ans[n - tot] = a[i], tot = tot + 1;
                    last = first - e[p]+1;
                }
                else
                {
                    for (int i = last; i >= first + e[p]; i--) ans[n - tot] = a[i], tot = tot + 1;
                    last = first + e[p] - 1; 
                }
                if (op[p] != flag)
                {
                    swap(first, last);
                    flag = op[p];
                }
            }
            if (tot < n)
            {
                if (first <= last) for (int i = last; i >= first; i--) ans[n - tot] = a[i], tot = tot + 1;
                else for (int i = last; i <= first; i++) ans[n - tot] = a[i], tot = tot + 1;
            }
    
            for (int i = 1; i <= n; i++) printf("%d ", ans[i]);
            printf("
    ");
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/zufezzt/p/5244283.html
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