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  • BZOJ 1878 [SDOI2009]HH的项链

    莫队算法。

    #include<cstdio>
    #include<cstring>
    #include<cmath>
    #include<queue>
    #include<algorithm>
    using namespace std;
    
    const int maxn = 50000 + 10;
    int cnt[1000000 + 10];
    int a[maxn], pos[maxn];
    int n, m, Ans, L, R;
    struct X
    {
        int l, r, id;
        int ans;
    }s[200000 + 10];
    int ans[200000 + 10];
    
    bool cmp(const X&a, const X&b)
    {
        if (pos[a.l] == pos[b.l]) return a.r<b.r;
        return a.l<b.l;
    }
    
    bool cmp1(const X&a, const X&b)
    {
        return a.id<b.id;
    }
    
    int main()
    {
        while (~scanf("%d", &n)) {
            int sz = sqrt(n); memset(cnt, 0, sizeof cnt);
            for (int i = 1; i <= n; i++)
            {
                scanf("%d", &a[i]);
                pos[i] = i / sz;
            }
            scanf("%d", &m);
            for (int i = 1; i <= m; i++)
            {
                scanf("%d%d", &s[i].l, &s[i].r);
                s[i].id = i;
            }
            sort(s + 1, s + m + 1, cmp);
            Ans = 0;
            for (int i = s[1].l; i <= s[1].r; i++)
            {
                cnt[a[i]]++;
                if (cnt[a[i]] == 1) Ans++;
            }
            ans[s[1].id] = Ans;
            L = s[1].l; R = s[1].r;
    
            for (int i = 2; i <= m; i++)
            {
                while (L < s[i].l)
                {
                    cnt[a[L]]--;
                    if (cnt[a[L]] == 0) Ans--;
                    L++;
                }
    
                while (L > s[i].l)
                {
                    L--;
                    cnt[a[L]]++;
                    if (cnt[a[L]] == 1) Ans++;
                }
    
                while (R > s[i].r)
                {
                    cnt[a[R]]--;
                    if (cnt[a[R]] == 0) Ans--;
                    R--;
                }
    
                while (R < s[i].r)
                {
                    R++;
                    cnt[a[R]]++;
                    if (cnt[a[R]] == 1) Ans++;
                }
                s[i].ans = Ans;
                ans[s[i].id] = Ans;
            }
    
            for (int i = 1; i <= m; i++)
                printf("%d
    ", ans[i]);
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/zufezzt/p/5399046.html
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