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  • PAT (Advanced Level) 1089. Insert or Merge (25)

    简单题。模拟一下即可。

    #include<cstdio>
    #include<cstring>
    #include<cmath>
    #include<vector>
    #include<map>
    #include<queue>
    #include<stack>
    #include<algorithm>
    using namespace std;
    
    const int maxn=200;
    int a[maxn],b[maxn],n;
    
    int main()
    {
        scanf("%d",&n);
        for(int i=1; i<=n; i++) scanf("%d",&a[i]);
        for(int i=1; i<=n; i++) scanf("%d",&b[i]);
    
        int flag=1;
    
        int p=n+1;
        for(int i=2;i<=n;i++)
            if(b[i]<b[i-1]) {p=i; break;}
    
        for(int i=p;i<=n;i++)
        {
            if(a[i]==b[i]) continue;
            else flag=0;
        }
    
        if(flag==1)
        {
            printf("Insertion Sort
    ");
            if(p==n+1) p=n;
            sort(a+1,a+p+1);
            for(int i=1; i<=p; i++)
            {
                printf("%d",a[i]);
                if(i<n) printf(" ");
                else printf("
    ");
            }
            for(int i=p+1; i<=n; i++)
            {
                printf("%d",a[i]);
                if(i<n) printf(" ");
                else printf("
    ");
            }
        }
        else
        {
            printf("Merge Sort
    ");
    
            int len=1;
            while(1)
            {
                int pp=1;
                while(1)
                {
                    if(pp+len-1>n)
                    {
                        sort(a+pp,a+n+1);
                        break;
                    }
                    else
                    {
                        sort(a+pp,a+pp+len);
                        pp=pp+len;
                    }
                }
    
                int fail=0;
                for(int i=1; i<=n; i++) if(a[i]!=b[i]) fail=1;
    
                if(fail==0)
                {
                    len=len*2;
                    int ppp=1;
                    while(1)
                    {
                        if(ppp+len-1>n)
                        {
                            sort(a+ppp,a+n+1);
                            break;
                        }
                        else
                        {
                            sort(a+ppp,a+ppp+len);
                            ppp=ppp+len;
                        }
                    }
                    for(int i=1;i<=n;i++)
                    {
                        printf("%d",a[i]);
                        if(i<n) printf(" ");
                        else printf("
    ");
                    }
                    break;
                }
                len=len*2;
            }
        }
    
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/zufezzt/p/5639074.html
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